我试图找到解决方案,以融合数字框架与字符colnames,并保持因子变量融化df.
我的数据的一个子集:
df <- structure(list(bloc = c(1L, 1L, 2L, 2L, 3L, 3L, 4L, 4L, 5L, 5L,
6L, 6L), name = c("Cristina", "Robijn", "Robijn", "Cristina",
"Robijn", "Cristina", "Cristina", "Robijn", "Robijn", "Cristina",
"Cristina", "Robijn"), d1 = c(0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0), d7 = c(0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0), d10 = c(1, 0,
0, 5, 0, 0.1, 1, 0, 0, 0.1, 0.1, 0), d13 = c(0, 0, 0, 0, 0, 0.1,
0.1, 0, 0, 0.1, 0, 0.1), d20 = c(0.1, 1, 5, 5, 5, 50, 5, 5, 5,
5, 25, 1), d24 = c(75, 5, 25, 100, 25, 75, 95, 5, 5, 100, 75,
25), d27 = c(75L, 5L, 50L, 100L, 50L, 100L, 100L, 50L, 50L, 100L,
100L, 25L), d34 = c(75L, 25L, 75L, 100L, 75L, 100L, 100L, 75L,
75L, 100L, 100L, 50L), d41 = c(75L, 25L, 95L, 100L, 100L, 100L,
100L, 95L, 95L, 100L, 100L, 75L), d48 = c(100L, 50L, 95L, 100L,
75L, 100L, 100L, 75L, 95L, 100L, 100L, 95L), d55 = c(100L, 75L,
100L, 100L, 100L, 100L, 100L, 100L, 100L, 100L, 100L, 100L)), row.names = c(1L,
2L, 43L, 44L, 60L, 62L, 78L, 80L, 95L, 96L, 112L, 117L), class = "data.frame")
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和代码:
data.table::melt(
df,
id.vars = c("bloc", "name"),
variable.name = "time",
value.name = "severity",
variable.factor = FALSE
) %>% str()
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发生这种情况的原因是因为df是数据帧.在这种情况下melt,data.table会回退到reshape2的行为,melt而reshape2没有variable.factor参数.
你可以在源代码中看到这个data.table::melt:
> data.table::melt
function (data, ..., na.rm = FALSE, value.name = "value")
{
if (is.data.table(data))
UseMethod("melt", data)
else reshape2::melt(data, ..., na.rm = na.rm, value.name = value.name)
}
<bytecode: 0x10f886b88>
<environment: namespace:data.table>
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因此,您的代码:
melt(
df,
id.vars = c("bloc", "name"),
variable.name = "time",
value.name = "severity",
variable.factor = FALSE
) %>% str()
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给你:
Run Code Online (Sandbox Code Playgroud)'data.frame': 132 obs. of 4 variables: $ bloc : int 1 1 2 2 3 3 4 4 5 5 ... $ name : chr "Cristina" "Robijn" "Robijn" "Cristina" ... $ time : Factor w/ 11 levels "d1","d7","d10",..: 1 1 1 1 1 1 1 1 1 1 ... $ severity: num 0 0 0 0 0 0 0 0 0 0 ...
然而,wrappring时df在setDT:
melt(
setDT(df),
id.vars = c("bloc", "name"),
variable.name = "time",
value.name = "severity",
variable.factor = FALSE
) %>% str()
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你会得到所需的输出:
Run Code Online (Sandbox Code Playgroud)Classes ‘data.table’ and 'data.frame': 132 obs. of 4 variables: $ bloc : int 1 1 2 2 3 3 4 4 5 5 ... $ name : chr "Cristina" "Robijn" "Robijn" "Cristina" ... $ time : chr "d1" "d1" "d1" "d1" ... $ severity: num 0 0 0 0 0 0 0 0 0 0 ... - attr(*, ".internal.selfref")=<externalptr>