目前我有两个代表excel电子表格的数据框.我希望加入日期相同的数据.这是一对多的连接,因为一张电子表格有一个日期,然后我需要添加具有相同日期的多行的数据
一个例子:
A B
date data date data
0 2015-0-1 ... 0 2015-0-1 to 2015-0-2 ...
1 2015-0-2 ... 1 2015-0-1 to 2015-0-2 ...
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在这种情况下,来自A的两行都将从B接收行0和1,因为它们在该范围内.
我试过用
df3 = pandas.merge(df2, df1, how='right', validate='1:m', left_on='Travel Date/Range', right_on='End')
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完成此操作但收到此错误.
Traceback (most recent call last):
File "<pyshell#61>", line 1, in <module>
df3 = pandas.merge(df2, df1, how='right', validate='1:m', left_on='Travel Date/Range', right_on='End')
File "C:\Users\M199449\AppData\Local\Programs\Python\Python36\lib\site-packages\pandas\core\reshape\merge.py", line 61, in merge
validate=validate)
File "C:\Users\M199449\AppData\Local\Programs\Python\Python36\lib\site-packages\pandas\core\reshape\merge.py", line 555, in __init__
self._maybe_coerce_merge_keys()
File "C:\Users\M199449\AppData\Local\Programs\Python\Python36\lib\site-packages\pandas\core\reshape\merge.py", line 990, in _maybe_coerce_merge_keys
raise ValueError(msg)
ValueError: You are trying to merge on object and datetime64[ns] columns. If you wish to proceed you should use pd.concat
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我当然可以根据需要添加更多信息
ALo*_*llz 12
所以这是合并的选项:
假设您有两个DataFrame:
import pandas as pd
df1 = pd.DataFrame({'date': ['2015-01-01', '2015-01-02', '2015-01-03'],
'data': ['A', 'B', 'C']})
df2 = pd.DataFrame({'date': ['2015-01-01 to 2015-01-02', '2015-01-01 to 2015-01-02', '2015-01-02 to 2015-01-03'],
'data': ['E', 'F', 'G']})
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现在做一些清洁,以获得您需要的所有日期,并确保它们 datetime
df1['date'] = pd.to_datetime(df1.date)
df2[['start', 'end']] = df2['date'].str.split(' to ', expand=True)
df2['start'] = pd.to_datetime(df2.start)
df2['end'] = pd.to_datetime(df2.end)
# No need for this anymore
df2 = df2.drop(columns='date')
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现在将它们合并在一起.你会得到99x10K行.
df = df1.assign(dummy=1).merge(df2.assign(dummy=1), on='dummy').drop(columns='dummy')
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并且属于范围之间的日期的子集:
df[(df.date >= df.start) & (df.date <= df.end)]
# date data_x data_y start end
#0 2015-01-01 A E 2015-01-01 2015-01-02
#1 2015-01-01 A F 2015-01-01 2015-01-02
#3 2015-01-02 B E 2015-01-01 2015-01-02
#4 2015-01-02 B F 2015-01-01 2015-01-02
#5 2015-01-02 B G 2015-01-02 2015-01-03
#8 2015-01-03 C G 2015-01-02 2015-01-03
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例如,如果一些日期df2是一个日期,因为我们正在使用,.str.split我们将获得None第二个日期.然后用.loc它来适当地设置它.
df2 = pd.DataFrame({'date': ['2015-01-01 to 2015-01-02', '2015-01-01 to 2015-01-02', '2015-01-02 to 2015-01-03',
'2015-01-03'],
'data': ['E', 'F', 'G', 'H']})
df2[['start', 'end']] = df2['date'].str.split(' to ', expand=True)
df2.loc[df2.end.isnull(), 'end'] = df2.loc[df2.end.isnull(), 'start']
# data start end
#0 E 2015-01-01 2015-01-02
#1 F 2015-01-01 2015-01-02
#2 G 2015-01-02 2015-01-03
#3 H 2015-01-03 2015-01-03
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现在其余部分保持不变
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