使用 jQuery 和 JavaScript 检查对象中的所有属性是否为空并将其替换为空字符串

Question

我有一个 JSON 对象，其中包括其他对象和对象列表。必须编写一个函数，它遍历对象的所有属性以及对象内的对象和对象列表，并null用空字符串替换。

由于它是循环内循环，我需要实现延迟顺序处理。我尝试了很多方法，但都失败了。任何人请帮忙。

function ValidateObject(result) {
  var aObj = result.A;
  aObj = VerifyForNull(aoBJ);
  var bObj = result.B;
  bObj = VerifyForNull(bObJ);
  for (var i = 0; i < result.C.length; i++) {
    var cObj = result.C[i];
    cObj = VerifyForNull(cObJ);
    for (var j = 0; j < cObj.D.length; j++) {
      var dObj = cObj.D[i];
      dObj = VerifyForNull(dObj);
    }
  }
}

function VerifyForNull(obj) {
  Object.keys(obj).forEach(function(key) {
    var val = obj[key];
    if (val == null || value === undefined) {
      obj[key] = "";
    }
  });
}

Answer 1

您可以使用JSON.Stringify（参见MDN）和替换方法来替换nulls 中的所有s Object：

console.log(replaceNull({
    x: {},
    y: null,
    z: [1,null,3,4],
    foo: "foo",
    bar: {foobar: null}
  }));

const yourObj = { "person": { "id": 12345, "name": "John Doe", "phones": { "home": "800-123-4567", "mobile": null }, "email": [ "jd@example.com", "jd@example.org" ], "dateOfBirth": null, "registered": true, "emergencyContacts": [ { "name": "Jane Doe", "phone": null, "relationship": "spouse" }, { "name": "Justin Doe", "phone": "877-123-1212", "relationship": undefined } ] } };

console.log(replaceNull(yourObj, ""));

function replaceNull(someObj, replaceValue = "***") {
  const replacer = (key, value) => 
    String(value) === "null" || String(value) === "undefined" ? replaceValue : value;
  //^ because you seem to want to replace (strings) "null" or "undefined" too
  
  return JSON.parse( JSON.stringify(someObj, replacer));
}