Jes*_*ess 5 rxjs angular rxjs6
我有一个HTTP GET请求,该请求返回要转换为多个可观察对象的多个对象。这是响应的示例:
{
lookup1:
[
{
"label": "lookup1 option 1",
"value": 1
},
{
"label": "lookup1 option 2",
"value": 2
}
],
lookup2:
[
{
"label": "lookup2 option 1",
"value": 1
},
{
"label": "lookup2 option 2",
"value": 2
}
]
}
Run Code Online (Sandbox Code Playgroud)
这是我得到的两个可观察值的服务:
this.lookup1 = this.apiService.get('/lookups/')
.pipe(map(response => response["lookup1"]));
this.lookup2 = this.apiService.get('/lookups/')
.pipe(map(response => response["lookup2"]));
Run Code Online (Sandbox Code Playgroud)
如何使用一个HTTP GET请求执行此操作?
请注意,这样的代码将执行2个HTTP GET请求:
let lookups = this.apiService.get('/lookups/');
this.lookup1 = lookups
.pipe(map(response => response["lookup1"]));
this.lookup2 = lookups
.pipe(map(response => response["lookup2"]));
Run Code Online (Sandbox Code Playgroud)
方法一
创建 2 个主题,请求解决后将更新这些主题。
let map1 = new Subject();
let map2 = new Subject();
this.lookup1 = map1.pipe(map(response => response["lookup1"]));
this.lookup2 = map2.pipe(map(response => response["lookup2"]));
this.apiService.get('/lookups/').subscribe( response => {
map1.next(response);
map2.next(response);
})
Run Code Online (Sandbox Code Playgroud)
方法2
您可以使用concatMap和from将一个流转换为另一个流。
this.apiService.get('/lookups/').pipe(
concatMap( responseJson => from(Object.values(responseJson)))
).subscribe( arrayElement=> console.log(arrayElement))
Run Code Online (Sandbox Code Playgroud)
输出 :
// first object emitted :
[
{
"label": "lookup1 option 1",
"value": 1
},
{
"label": "lookup1 option 2",
"value": 2
}
]
// second object emitted :
[
{
"label": "lookup2 option 1",
"value": 1
},
{
"label": "lookup2 option 2",
"value": 2
}
]
Run Code Online (Sandbox Code Playgroud)
concatMap 接受一个 Observable 并发出另一个 Observable。
from 将可迭代元素转换为流。您将获得与可迭代中的项目一样多的排放量。
| 归档时间: |
|
| 查看次数: |
2750 次 |
| 最近记录: |