显示每个值从数组中计数

Question

我有一个string[]像这样的价值观

string[] s = { "saravanan", "Karthick", "Jackson", "saravanan" };

我想看下面的输出

saravanan发生2次
Karthick发生1次
Jackson发生1次

如何在不使用 List或的情况下执行此操作Dictionary

这是我到目前为止所尝试的:

int i, j;
String[] s = {"saravanan", "Karthick", "Jackson", "saravanan"}

Console.WriteLine("Number of Times occured Each Values");

for (i = 0; i < s.Length; i++)
{
    int count = 0;
    for (j = 0; j < s.Length; j++)
    {
        if (s[i] == (s[j]))
        {
            count++;
        }
    }

    Console.WriteLine(s[i]+"is count="+count);
}

该代码产生此输出:

发生的次数每个值 saravananis
计数= 2
Karthickis计数= 1
Jacksonis计数= 1
saravananis计数= 2

Answer 1

通常,我们通过Linq解决这些问题(查询)

  string[] s = new[] { 
    "saravanan", "Karthick", "Jackson", "saravanan" };

  var result = string.Join(Environment.NewLine, s
    .GroupBy(item => item)
    .Select(chunk => $"{chunk.Key} occures {chunk.Count()} times"));

  Console.Write(result);

在的情况下,嵌套循环(当前的代码),我们应该不会打印出相同的名字多次.让我们来介绍bool appeared一下之前是否出现了名字

   string[] s = new[] { 
     "saravanan", "Karthick", "Jackson", "saravanan" };

   for (i = 0; i < s.Length; i++) {
     int count = 0;
     bool appeared = false;

     for (j = 0; j < s.Length; j++) {
       if (s[i] == (s[j])) {
         // Names are same. Do we have the name before?
         if (j < i) {
           // If yes we have no need to loop any more
           appeared = true;

           break;
         }

         count++;
       }
     }

    // if name has been appeared already we shouldn't print it out 
    if (!appeared) 
      Console.WriteLine(s[i] + "is count=" + count);
  }