如何使用http库捕获SocketException？

Question

其他人已经指出了这个问题（例如here）。尽管我可能已经理解了原因，但是在使用更高级别的http库时仍然找不到解决方案。例如：

import 'package:http/http.dart';

// yes, pwd is String, it's just a test...
Future<Response> login(String user, String pwd) {
  final authHeader = encodeBasicCredentials(user, pwd);
  return get(
    'http://192.168.0.100:8080/login',
    headers: <String, String>{
    HttpHeaders.AUTHORIZATION: authHeader,
    },
  ));
}

SocketException例如，如果无法访问主机（在我的情况下，错误的主机ip），我将找不到捕获被抛出的邮件的方法。我尝试将awaitin 包装try/catch或使用Future.catchError。

这是异常的堆栈跟踪：

[ERROR:topaz/lib/tonic/logging/dart_error.cc(16)] Unhandled exception:
E/flutter ( 4036): SocketException: OS Error: Connection refused, errno = 111, address = 192.168.0.100, port = 35588
E/flutter ( 4036): #0      IOClient.send (package:http/src/io_client.dart:30:23)
E/flutter ( 4036): <asynchronous suspension>
E/flutter ( 4036): #1      BaseClient._sendUnstreamed (package:http/src/base_client.dart:171:38)
E/flutter ( 4036): <asynchronous suspension>
E/flutter ( 4036): #2      BaseClient.get (package:http/src/base_client.dart:34:5)
E/flutter ( 4036): #3      get.<anonymous closure> (package:http/http.dart:47:34)
E/flutter ( 4036): #4      _withClient (package:http/http.dart:167:20)
E/flutter ( 4036): <asynchronous suspension>
E/flutter ( 4036): #5      get (package:http/http.dart:47:3)

Answer 1

您可以检查异常的类型并相应地处理它，例如：

Future<Response> login(String user, String pwd) async {
  final String authHeader = encodeBasicCredentials(user, pwd);
  try {
    return await get(
        'http://192.168.0.100:8080/login',
        headers: {
          HttpHeaders.AUTHORIZATION: authHeader,
        },
      );
  } catch (e) {
    if(e is SocketException){
       //treat SocketException
       print("Socket exception: ${e.toString()}");
    }
    else if(e is TimeoutException){
       //treat TimeoutException
       print("Timeout exception: ${e.toString()}");
    }
    else print("Unhandled exception: ${e.toString()}");
  }
}

最好创建一个错误处理程序库，这样您就可以像handleException(e);在 catch 块上那样调用函数。

Answer 2

您可以将其更改login为async以便等待响应。这样您就可以捕获异常（例如，返回null而不是Response）。

Future<Response> login(String user, String pwd) async {
  final String authHeader = encodeBasicCredentials(user, pwd);
  try {
    return await get(
        'http://192.168.0.100:8080/login',
        headers: {
          HttpHeaders.AUTHORIZATION: authHeader,
        },
      );
  } catch (e) {
    print(e);
    return null;
  }
}