C程序从bash脚本运行时内存泄漏

Question

我有一个C程序,它采用各种命令行参数,即

./Coupled arg1 argv2

当我和valgrind一起运行时

valgrind ./Coupled arg1 arg2

我没有内存泄漏.但是当我使用bash脚本,叫run形式,

arg1=thing1
arg2=thing2

./Coupled $thing1 $thing2

然后跑

valgrind ./run

我得到了很多仍然可以访问的内存泄漏.我已经读过,仍然可以访问内存泄漏不是一个大问题,但我很想知道为什么会发生这种情况？当用--leak-check=full --show-leak-kinds=all标志运行valgrind时,输出的一个示例位(完整的valgrind输出是多页长)

==4518== 1 bytes in 1 blocks are still reachable in loss record 1 of 269
==4518==    at 0x4C29BE3: malloc (vg_replace_malloc.c:299)
==4518==    by 0x46A3DA: xmalloc (in /usr/bin/bash)
==4518==    by 0x437219: make_variable_value (in /usr/bin/bash)
==4518==    by 0x438230: ??? (in /usr/bin/bash)
==4518==    by 0x43A35E: initialize_shell_variables (in /usr/bin/bash)
==4518==    by 0x41DD92: ??? (in /usr/bin/bash)
==4518==    by 0x41C482: main (in /usr/bin/bash)

Answer 1

valgrind ./run将调试shell而不是您的程序.

看一下输出,看看它是如何提到的(例如)

== 4518 == by 0x41C482:main(在/ usr/bin/bash中)

_{[强调我的]}

如果要调试程序,则需要valgrind 在脚本中运行:

arg1=thing1
arg2=thing2

valgrind ./Coupled $thing1 $thing2