我需要将字符串格式化为x个字符,但我格式化的值可以是任意长度.
"" => " "
"New York" => "New York "
"New York City" => "New York C"
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目前,我这样做:
$"{(address.City.Substring(0, address.City.Length > 20 ? 20 : address.City.Length)),20}"
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我这样做变得相当繁琐且容易出错:
var builder = new StringBuilder();
builder.AppendLine($"{(address.Street1.Substring(0, address.Street1.Length > 30 ? 30 : address.Street1.Length)),30}");
builder.AppendLine($"{(address.Street2.Substring(0, address.Street2.Length > 30 ? 30 : address.Street2.Length)),30}");
builder.AppendLine($"{(address.City.Substring(0, address.City.Length > 20 ? 20 : address.City.Length)),20}");
builder.AppendLine($"{(address.State.Substring(0, address.State.Length > 5 ? 5 : address.State.Length)),5}");
builder.AppendLine($"{(address.Zip.Substring(0, address.Zip.Length > 10 ? 10 : address.Zip.Length)),10}");
var result = builder.ToString();
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而且我还需要做大约30件其他事情.如果有这样的事情,那将是非常好的:
address.City.SubstringExact(0, 20)
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你可以只添加一个扩展方法到字符串,这将为你做到这一点:
public static class StringExtensions
{
public static string ToLength(this string self, int length)
{
if(self == null)
return null;
return self.Length > length ? self.Substring(0, length) : self.PadRight(length);
}
}
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