如何在 JPQL 中使用别名

M_L*_*ude 3 java spring h2 jpql spring-data-jpa

我正在尝试从 H2 db 表中获取一些值。做我需要的查询是这样的:

SELECT cast(creationDate as date) as DATE, SUM(paymentValue) as TOTAL,fxRate 
FROM payment 
group by DATE
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其中“creationDate”、“paymentValue”、“fxRate”是“payment”表的列。CreationDate 是一个时间戳,所以我只需要从中获取日期。当我尝试用 Java 编写它时

 @Query("SELECT cast(creationDate as date) as daydate , SUM(paymentValue) as value1, fxRate as value2 FROM payment " + 
            "group by cast(creationDate as date)")
    List<Payment> findPaymentValuePerDay ();
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我收到错误 [Ljava.lang.Object; cannot be cast to ...entity.Payment.

我还尝试使用一个名为 GraphDto 的不同对象,它具有属性 daydate、value1 和 value2

@Query("SELECT cast(creationDate as date) as daydate , SUM(paymentValue) as value1, fxRate as value2 FROM payment " + 
            "group by cast(creationDate as date)")
    List<GraphDto> findPaymentValuePerDay ();
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但我得到了同样的错误。

 [Ljava.lang.Object; cannot be cast to ...entity.GraphDto.
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那么,如何在 JPQL 中使用别名?我只需要一个函数,该函数返回 3 个不同列的名称,其中的值使用正确的 H2 查询从现有实体中获取。谢谢你们

YCF*_*F_L 5

您的查询返回一个数组Object[]而不是GraphDtoObject,您有多种方法可以解决此问题:

解决方案1

创建一个构造函数,其中包含daydate, value1,value2

@Entity
public class GraphDto{

    private Date daydate;
    private Long value1;
    private Long value2;

    public GraphDto(Date daydate, Long value1, Long value2){
        //...
    }
    //..getters and setters
}
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那么您的查询应如下所示:

SELECT NEW com.packagename.GraphDto(cast(creationDate AS date), SUM(paymentValue), fxRate)
FROM payment
GROUP BY cast(creationDate AS date)
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解决方案2

将返回类型更改为:

List<Object[]> findPaymentValuePerDay ();
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然后在您的服务循环中遍历此对象并提取值:

List<Object[]> listObject = rep.findPaymentValuePerDay();
for(Object[] obj : listObject){
   Date date = (Date) obj[0];
   Long value1 = (Long) obj[1];
   Long value2 = (Long) obj[2];
}
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