0 r data.table
如何在data.table中随机采样例如三组,以使结果包含三组,其中原始data.table中的所有行均如此?
library(data.table)
dat <- data.table(ids=1:20, groups=sample(x=c("A","B","C", "D", "E", "F"), 20,
replace=TRUE))
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我知道如何从data.table中随机选择10行:
dat.sampl1 <- as.data.table(sapply(dat[], sample, 10))
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还有如何按组抽样
dat[,.SD[sample(.N, min(.N,3))], by = groups]
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但是如何随机分组?因此结果应如下所示:
ids groups
1 F
11 F
3 F
18 F
8 A
9 A
10 A
17 A
19 A
12 E
14 E
16 E
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您的意思是:
set.seed(123)
dat <- data.table(ids=1:20, groups=sample(x=c("A","B","C", "D", "E", "F"), 20,
replace=TRUE))
dat[groups %in% sample(unique(dat[, groups]), size = 3)][order(groups)]
# ids groups
# 1: 3 C
# 2: 10 C
# 3: 12 C
# 4: 7 D
# 5: 9 D
# 6: 14 D
# 7: 4 F
# 8: 5 F
# 9: 8 F
# 10: 11 F
# 11: 16 F
# 12: 20 F
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如果要对具有replacement的组进行抽样,则可以执行以下操作,其中A两次已被抽样:
dat[unique(dat[, list(groups)])[sample(.N, 3, replace = TRUE)], on = "groups"]
# ids groups
# 1: 3 C
# 2: 10 C
# 3: 12 C
# 4: 6 A
# 5: 15 A
# 6: 18 A
# 7: 6 A
# 8: 15 A
# 9: 18 A
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