Json.NET - 序列化没有属性名称的泛型类型包装器

Question

我有一个通用类型，它包装一个原始类型以赋予它值相等语义

public class ValueObject<T>
{
    public T Value { get; }
    public ValueObject(T value) => Value = value;

    // various other equality members etc...
}

它的用法如下：

public class CustomerId : ValueObject<Guid>
{
    public CustomerId(Guid value) : base(value) { }
}

public class EmailAddress : ValueObject<string>
{
    public EmailAddress(string value) : base(value) { }
}

问题是在序列化类型时，例如：

public class Customer
{
    public CustomerId Id { get; }
    public EmailAddress Email { get; }

    public Customer(CustomerId id, EmailAddress email) 
    { 
        Id = id;
        Email = email;
    }
}

继承自的每个对象ValueObject<T>都包含在一个Value属性中（如预期的那样）。例如

var customerId = new CustomerId(Guid.NewGuid());
var emailAddress = new EmailAddress("some@email.com");

var customer = new Customer(customerId, emailAddress);

var customerAsJson = JsonConvert.SerializeObject(customer, Formatting.Indented, new JsonSerializerSettings
{
    ContractResolver = new CamelCasePropertyNamesContractResolver() 
})

结果是

{
  "id": {
    "value": "f5ce21a5-a0d1-4888-8d22-6f484794ac7c"
  },
  "email": {
    "value": "some@email.com"
  }
}

有没有办法编写自定义，JsonConverter以便Value为类型子类化排除该属性，ValueObject<T>以便上面的示例输出

{
  "id": "f5ce21a5-a0d1-4888-8d22-6f484794ac7c",
  "email": "some@email.com"
}

我宁愿有一个JsonConverter可以处理所有的，ValueObject<T>而不是必须JsonConverter为每个ValueObject<T>子类定义一个单独的

我的第一次尝试是

public class ValueObjectOfTConverter : JsonConverter
{
    private static readonly Type ValueObjectGenericType = typeof(ValueObject<>);
    private static readonly string ValuePropertyName = nameof(ValueObject<object>.Value);

    public override bool CanConvert(Type objectType) =>
        IsSubclassOfGenericType(objectType, ValueObjectGenericType);

    public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
    {
        // converts "f5ce21a5-a0d1-4888-8d22-6f484794ac7c" => "value": "f5ce21a5-a0d1-4888-8d22-6f484794ac7c"
        var existingJsonWrappedInValueProperty = new JObject(new JProperty(ValuePropertyName, JToken.Load(reader)));
        return existingJsonWrappedInValueProperty.ToObject(objectType, serializer);
    }

    public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
    {
        // to implement
    }

    private static bool IsSubclassOfGenericType(Type typeToCheck, Type openGenericType)
    {
        while (typeToCheck != null && typeToCheck != typeof(object))
        {
            var cur = typeToCheck.IsGenericType ? typeToCheck.GetGenericTypeDefinition() : typeToCheck;
            if (openGenericType == cur) return true;

            typeToCheck = typeToCheck.BaseType;
        }

        return false;
    }
}

Answer 1

您可以使用类似于Json.Net: Serialize/Deserialize property as a value, not as an object 中所示的自定义JsonConverter来执行此操作。但是，由于没有非通用方法来获取和设置为对象，因此您将需要使用反射。 ValueObject<T>Value

这是一种方法：

class ValueConverter : JsonConverter
{
    static Type GetValueType(Type objectType)
    {
        return objectType
            .BaseTypesAndSelf()
            .Where(t => t.IsGenericType && t.GetGenericTypeDefinition() == typeof(ValueObject<>))
            .Select(t => t.GetGenericArguments()[0])
            .FirstOrDefault();
    }

    public override bool CanConvert(Type objectType)
    {
        return GetValueType(objectType) != null;
    }

    public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
    {
        // You need to decide whether a null JSON token results in a null ValueObject<T> or 
        // an allocated ValueObject<T> with a null Value.
        if (reader.SkipComments().TokenType == JsonToken.Null)
            return null;
        var valueType = GetValueType(objectType);
        var value = serializer.Deserialize(reader, valueType);

        // Here we assume that every subclass of ValueObject<T> has a constructor with a single argument, of type T.
        return Activator.CreateInstance(objectType, value);
    }

    const string ValuePropertyName = nameof(ValueObject<object>.Value);

    public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
    {
        var contract = (JsonObjectContract)serializer.ContractResolver.ResolveContract(value.GetType());
        var valueProperty = contract.Properties.Where(p => p.UnderlyingName == ValuePropertyName).Single();
        // You can simplify this to .Single() if ValueObject<T> has no other properties:
        // var valueProperty = contract.Properties.Single();
        serializer.Serialize(writer, valueProperty.ValueProvider.GetValue(value));
    }
}

public static partial class JsonExtensions
{
    public static JsonReader SkipComments(this JsonReader reader)
    {
        while (reader.TokenType == JsonToken.Comment && reader.Read())
            ;
        return reader;
    }
}

public static class TypeExtensions
{
    public static IEnumerable<Type> BaseTypesAndSelf(this Type type)
    {
        while (type != null)
        {
            yield return type;
            type = type.BaseType;
        }
    }
}

然后，您可以直接应用转换器，ValueType<T>如下所示：

[JsonConverter(typeof(ValueConverter))]
public class ValueObject<T>
{
    // Remainder unchanged
}

或者在设置中应用它：

var settings = new JsonSerializerSettings
{
    Converters = { new ValueConverter() },
    ContractResolver = new CamelCasePropertyNamesContractResolver() 
};
var customerAsJson = JsonConvert.SerializeObject(customer, Formatting.Indented, settings);

工作示例 .Net fiddle #1在这里。

或者，您可以考虑添加一个非泛型方法来访问值作为object，例如像这样：

public interface IHasValue
{
    object GetValue(); // A method rather than a property to ensure the non-generic value is never serialized directly.
}

public class ValueObject<T> : IHasValue
{
    public T Value { get; }
    public ValueObject(T value) => Value = value;

    // various other equality members etc...

    #region IHasValue Members

    object IHasValue.GetValue() => Value;

    #endregion
}

有了这个添加，WriteJson()就变得简单多了：

    public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
    {
        serializer.Serialize(writer, ((IHasValue)value).GetValue());
    }

工作示例 .Net fiddle #2在这里。

笔记：

• ReadJson()假设 的每个子类Value<T>都有一个公共构造函数，它接受一个类型为 的参数T。

• 将转换器直接应用到ValueType<T>using[JsonConverter(typeof(ValueConverter))]将有稍微好一点的性能，因为CanConvert永远不需要被调用。有关详细信息，请参阅性能提示：JsonConverters。

• 您需要决定如何处理nullJSON 令牌。它应该导致 nullValueType<T>还是分配ValueType<T>了 null Value？

• 在ValueType<T>我IHasValue.GetValue()明确实现的第二个版本中，ValueType<T>在静态类型代码中使用实例的情况下，不鼓励使用它。

• 如果您真的只想将转换器应用于类型子类化 ValueObject<T>而不是ValueObject<T>其本身，请GetValueType(Type objectType)添加对.Skip(1)：

  static Type GetValueType(Type objectType)
  {
      return objectType
          .BaseTypesAndSelf()
          .Skip(1) // Do not apply the converter to ValueObject<T> when not subclassed
          .Where(t => t.IsGenericType && t.GetGenericTypeDefinition() == typeof(ValueObject<>))
          .Select(t => t.GetGenericArguments()[0])
          .FirstOrDefault();
  }
  

  然后将转换器应用于JsonSerializerSettings.Converters而不是直接应用于ValueObject<T>.