kos*_*eat 12 unit-testing asynchronous jasmine angular angular-calendar
我有一个失败的异步角度组件DOM测试,但它的同步等效失败,我不明白为什么.
这是茉莉花测试:
describe('Availability Component', () => {
let fixture: ComponentFixture<AvailabilityComponent>;
const absenceService = jasmine.createSpyObj('AbsenceService', ['findAbsences']);
absenceService.findAbsences.and.returnValue(of([{}]));
beforeEach(async(() => {
TestBed.configureTestingModule({
declarations: [AvailabilityComponent],
imports: [CalendarModule.forRoot()],
providers: [{provide: AbsenceService, useValue: absenceService}]
}).compileComponents();
}));
beforeEach(() => {
fixture = TestBed.createComponent(AvailabilityComponent);
});
const printAbsenceReasons = function () {
console.log(fixture.debugElement.queryAll(By.css('.calendarAbsence'))
.map(e => e.nativeElement.textContent)
.join(','));
};
it('should synchronously find absences in calendar view', () => {
fixture.detectChanges();
console.log('synchronous test');
printAbsenceReasons();
});
it('should asynchronously find absences in calendar view', fakeAsync(() => {
fixture.detectChanges();
tick();
fixture.detectChanges();
tick();
console.log('asynchronous test');
printAbsenceReasons();
}));
});
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这在同步情况下创建了正确的输出,但在异步情况下不正确:
LOG: 'processing absences'
HeadlessChrome 0.0.0 (Mac OS X 10.13.4): Executed 0 of 51 SUCCESS (0 secs / 0 secs)
LOG: 'synchronous test'
HeadlessChrome 0.0.0 (Mac OS X 10.13.4): Executed 0 of 51 SUCCESS (0 secs / 0 secs)
LOG: 'A,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,'
HeadlessChrome 0.0.0 (Mac OS X 10.13.4): Executed 0 of 51 SUCCESS (0 secs / 0 secs)
ERROR: 'Spec 'Availability Component should synchronously find absences in calendar view' has no expectations.'
HeadlessChrome 0.0.0 (Mac OS X 10.13.4): Executed 0 of 51 SUCCESS (0 secs / 0 secs)
LOG: 'processing absences'
HeadlessChrome 0.0.0 (Mac OS X 10.13.4): Executed 1 of 51 SUCCESS (0 secs / 0 secs)
LOG: 'asynchronous test'
HeadlessChrome 0.0.0 (Mac OS X 10.13.4): Executed 1 of 51 SUCCESS (0 secs / 0 secs)
LOG: ''
HeadlessChrome 0.0.0 (Mac OS X 10.13.4): Executed 1 of 51 SUCCESS (0 secs / 0 secs)
ERROR: 'Spec 'Availability Component should asynchronously find absences in calendar view' has no expectations.'
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我不确定这是否与我正在使用的角度日历组件有关,或者它是否与我的测试代码更基本的问题.
这里参考我的组件,模板和服务代码:
@Component({
selector: 'app-availability',
templateUrl: './availability.component.html',
styleUrls: ['availability.component.scss']
})
export class AvailabilityComponent implements OnInit {
viewDate: Date = new Date();
absenceEvents: CalendarEvent[] = [];
constructor(private absenceService: AbsenceService) {
}
ngOnInit() {
this.getAbsences();
}
getAbsences() {
this.absenceService.findAbsences()
.subscribe(ignored => {
console.log('processing absences');
this.absenceEvents = [{
start: new Date(2018, 3, 29), title: 'A'
}];
});
}
getAbsence(events: CalendarEvent[]) {
return events[0] ? events[0].title : '';
}
}
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模板代码:
<div>
<div>
<mwl-calendar-month-view
[viewDate]="viewDate"
[events]="absenceEvents"
[cellTemplate]="availabilityCellTemplate">
</mwl-calendar-month-view>
</div>
<ng-template #availabilityCellTemplate let-day="day">
<div class="calendarAbsence">{{ getAbsence(day.events) }}</div>
</ng-template>
</div>
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服务代码:
@Injectable()
export class AbsenceService {
private url = environment.APP_SHIFT_SERVICE_BASE_URL + '/api/absences';
constructor(private http: HttpClient) {
}
findAbsences(): Observable<Absence[]> {
console.error('Actual findAbsences() called');
return this.http.get<Absence[]>(this.url);
}
}
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不幸的是,这似乎与 fakeAsync 区域特别有关,而不是特别与异步测试有关。
我已经成功地获得了一个可用的异步测试async来代替fakeAsync:
it('should asynchronously find absences in calendar view', async(() => {
fixture.detectChanges();
fixture.whenStable().then(() => {
console.log('asynchronous test');
printAbsenceReasons(fixture);
expect(getAbsenceElements(fixture).length).toEqual(35);
});
});
}));
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我已经调试了失败fakeAsync和成功的同步测试。getMonthView它们都调用与“angular-calendar”同一作者在库“calendar-utils”中
调用的方法: https ://github.com/mattlewis92/calendar-utils/blob/master/src/calendar-utils.ts
在这个方法中,日期参数和其他日期计算本身似乎都出错了。
目前我只能假设它与zone.js 中的这个已知问题有关。我使用的是 Angular 5.2,但我认为它仍然相关。无论如何,我确信我的测试代码基本上是正确的,但问题出在其他地方。
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