Hes*_*loo 1 javascript arrays sorting algorithm loops
我有一个像这样的对象数组.我想摆脱重复的密钥(名称),只有一个名称,其中包含数组中所有相关的值.
let array = [
{ name: "dimensions", value: "dimensions value 1" },
{ name: "weight", value: "weight value 1" },
{ name: "dimensions", value: "dimensions value 2" },
{ name: "weight", value: "weight value 3" },
{ name: "dimensions", value: "dimensions value 3" },
{ name: "weight", value: "weight value 3" }
]
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我想把它变成这样的东西:
result = [ {
name : "dimensions",
values : ["dimention value 1", "dimention value 2", "dimention value 3"]
}, {
name : "weights",
values : ["weight value 1", "weight value 2", "weight value 3"]
} ]
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注意:数组中对象的计数是可变的."重量","尺寸","颜色","品牌"等......
到目前为止我尝试过的:
let flags = [], output = [], l = array.length;
for (let i = 0; i < l; i++) {
if (flags[array[i].name])
continue;
flags[array[i].name] = array[i].name;
output.push({
name : array[i].name,
values : [array[i].value]
});
}
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它返回如下内容:
[
{ name: "dimensions", values: [ "dimensions value 1"] },
{ name: "weight", values: [ "weight value 1"] }
]
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let array = [
{ name: "dimensions", value: "dimensions value 1" },
{ name: "weight", value: "weight value 1"},
{ name: "dimensions", value: "dimensions value 2"},
{ name: "weight", value: "weight value 3"},
{ name: "dimensions", value: "dimensions value 3"},
{ name: "weight", value: "weight value 3" }
]
let flags = [], output = [], l = array.length;
for (let i = 0; i < l; i++) {
if (flags[array[i].name])
continue;
flags[array[i].name] = array[i].name;
output.push({
name: array[i].name,
values: [array[i].value]
});
}
console.log(output);
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您可以使用array#reducewith Object.values()来对数组进行分组name.
let array = [ {name: "dimensions", value: "dimensions value 1"}, {name: "weight", value: "weight value 1"}, {name: "dimensions", value: "dimensions value 2"}, {name: "weight", value: "weight value 3"}, {name: "dimensions", value: "dimensions value 3"},{name: "weight", value: "weight value 3"} ],
result = Object.values(array.reduce((r,{name, value}) => {
r[name] = r[name] || {name, values : []};
r[name].values.push(value);
return r;
},{}));
console.log(result);Run Code Online (Sandbox Code Playgroud)