获取对象数组中重复键的值

Hes*_*loo 1 javascript arrays sorting algorithm loops

我有一个像这样的对象数组.我想摆脱重复的密钥(名称),只有一个名称,其中包含数组中所有相关的值.

let array = [ 
  { name: "dimensions", value: "dimensions value 1" },
  { name: "weight",     value: "weight value 1" },
  { name: "dimensions", value: "dimensions value 2" },
  { name: "weight",     value: "weight value 3" },
  { name: "dimensions", value: "dimensions value 3" },
  { name: "weight",     value: "weight value 3" } 
]
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我想把它变成这样的东西:

result = [ {
  name : "dimensions", 
  values : ["dimention value 1", "dimention value 2", "dimention value 3"] 
    }, {
  name : "weights", 
  values : ["weight value 1", "weight value 2", "weight value 3"] 
} ]
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注意:数组中对象的计数是可变的."重量","尺寸","颜色","品牌"等......

到目前为止我尝试过的:

let flags = [], output = [], l = array.length;

for (let i = 0; i < l; i++) {
    if (flags[array[i].name])
      continue;

    flags[array[i].name] = array[i].name;

    output.push({
        name : array[i].name,
        values : [array[i].value]
    });
}
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它返回如下内容:

[
  { name: "dimensions", values: [ "dimensions value 1"] },
  { name: "weight",     values: [ "weight value 1"] }
]
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let array = [
  { name: "dimensions", value: "dimensions value 1" },
  { name: "weight",     value: "weight value 1"},
  { name: "dimensions", value: "dimensions value 2"},
  { name: "weight",     value: "weight value 3"},
  { name: "dimensions", value: "dimensions value 3"},
  { name: "weight",     value: "weight value 3" }
]

let flags = [], output = [], l = array.length;

for (let i = 0; i < l; i++) {
  if (flags[array[i].name])
    continue;

  flags[array[i].name] = array[i].name;

  output.push({
    name: array[i].name,
    values: [array[i].value]
  });
}

console.log(output);
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Has*_*mam 5

您可以使用array#reducewith Object.values()来对数组进行分组name.

let array = [ {name: "dimensions", value: "dimensions value 1"}, {name: "weight", value: "weight value 1"}, {name: "dimensions", value: "dimensions value 2"}, {name: "weight", value: "weight value 3"}, {name: "dimensions", value: "dimensions value 3"},{name: "weight", value: "weight value 3"} ],
  result = Object.values(array.reduce((r,{name, value}) => {
    r[name] = r[name] || {name, values : []};
    r[name].values.push(value);
    return r;
  },{}));
console.log(result);
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