如何缩短StackExchange的SQL查询？

Question

我试图跟踪我的表现在这里SO使用StackExchange -查询堆栈溢出,并用此查询想出了:

首先,我有这个来获取我回答的问题列表:

Select Distinct a.Id, a.CreationDate, u.DisplayName, p.Title, p.Tags, 
   CONCAT('http://stackoverflow.com/questions/', p.Id, '#answer-', a.Id) as Link
From Posts a 
   Inner Join Posts p On a.ParentId = p.Id 
   Inner Join Users u On a.OwnerUserId = u.Id
   Inner Join PostTags pt on p.Id = Pt.PostId
   Inner Join Tags t on pt.TagId = t.Id
Where a.OwnerUserId in (
  9461114   --Me
  )
  And a.PostTypeId = 2  -- Answer
  And p.PostTypeId = 1  -- Question
  And t.TagName in ('jquery')

然后我做了另一个查询来获得所有答案的原始分数(Upvote,Downvote,Accepted)

SELECT *
FROM (
  SELECT v.PostID as Id, vt.Name, COUNT(*) AS CNT
     FROM 
     Posts p
       INNER JOIN Votes v
         ON v.PostId = p.Id
       INNER JOIN VoteTypes vt
         ON v.VoteTypeId = vt.Id
     WHERE
     p.OwnerUserId in
     (
      9461114   --Me
      ) 
  GROUP BY 
  vt.Name, v.PostID) s_tab pivot (min(CNT)for [Name] in ([UpMod], [DownMod],[AcceptedByOriginator]))AS PVT

然后为了使事情变得更容易,我曾经LEFT JOIN合并了我的两个查询,这就是我想出的:

Select a.Id, a.CreationDate, a.DisplayName, a.Title, a.Tags, a.Link, b.UpMod as Upvote, b.DownMod as DownVote, b.AcceptedByOriginator as Accepted
From 
(Select Distinct a.Id, a.CreationDate, u.DisplayName, p.Title, p.Tags, 
   CONCAT('http://stackoverflow.com/questions/', p.Id, '#answer-', a.Id) as Link
From Posts a 
   Inner Join Posts p On a.ParentId = p.Id 
   Inner Join Users u On a.OwnerUserId = u.Id
   Inner Join PostTags pt on p.Id = Pt.PostId
   Inner Join Tags t on pt.TagId = t.Id
Where a.OwnerUserId in (
  9461114   --Me
  )
  And a.PostTypeId = 2  -- Answer
  And p.PostTypeId = 1  -- Question
  And t.TagName in ('jquery')
  ) a 
Left Join 
  (SELECT *
FROM (
  SELECT v.PostID as Id, vt.Name, COUNT(*) AS CNT
     FROM 
     Posts p
       INNER JOIN Votes v
         ON v.PostId = p.Id
       INNER JOIN VoteTypes vt
         ON v.VoteTypeId = vt.Id
     WHERE
     p.OwnerUserId in
     (
      9461114   --Me
      ) 
  GROUP BY 
  vt.Name, v.PostID) s_tab pivot (min(CNT)for [Name] in ([UpMod], [DownMod],[AcceptedByOriginator]))AS PVT
  ) b on a.Id = b.Id

这太长了,我觉得还有其他方法可以做到这一点,而不会使查询看起来像这样.

我已经尝试并测试了我的查询,并且我确信它的工作方式与我想要的一样.我只是希望它更短.提前致谢!