static void Main(string[] args)
{
List<int> Allnumber = new List<int>();
Random rnd = new Random();
while (true)
{
int dice = rnd.Next(1, 100);
Console.WriteLine("Random number between 1 and 100 : {0}", dice);
Allnumber.Add(dice);
if (dice == 1)
break;
}
Console.WriteLine();
Console.WriteLine("Allnumber : " + string.Join(" ", Allnumber));
List<int> Odd = (from number in Allnumber where number % 2 != 0 select number).ToList();
List<int> Even = new List<int>(from number in Allnumber where number % 2 == 0 select number);
Console.WriteLine("Odd : " + string.Join(" ", Odd));
Console.WriteLine("Even : " + string.Join(" ", Even));
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我想制作一个新列表,其中包括来自Allnumber列表的3个.它应该包含所有具有3(3,13,23,33,34,36,39,43,53 ......)的数字.无论如何只拿3s?我发现有Findall,Contain方法但不能用于int类型列表.谢谢你们每个人都不能相信有这么多方法可以做到:D
我会将此签入移至单独的方法
public static bool ContainsDigit(int input, int digit)
{
do
{
if (input % 10 == digit)
{
return true;
}
input /= 10;
}
while (input > 0);
return false;
}
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用法:
List<int> result = Allnumber.Where(x => ContainsDigit(x, 3)).ToList();
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https://dotnetfiddle.net/2ZPNbM
一行中的方法相同
List<int> Allnumber = Enumerable.Range(0, 100).ToList();
List<int> result = Allnumber.Where(x => { do { if (x % 10 == 3) return true; } while ((x /= 10) > 0); return false; }).ToList();
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性能(Allnumber with 1000000numbers):
|------------------------------------------------------|
| User | Method | Time |
|------------|--------------------------+--------------|
| fubo | ContainsDigit() | 0,03 seconds |
| JamieC | ToString().Contains("3") | 0,20 seconds |
| TheGeneral | WhereDigit() | 0,10 seconds |
| TheGeneral | InternalRun() | 0,04 seconds |
|------------------------------------------------------|
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dotnetfiddle并不真正适用于benachmarking - 每次运行都有所不同,可能是因为dotnetfiddle的负载,我只能使用100,000而不是1,000,000数字但是... https://dotnetfiddle.net/pqCx2J
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