建立失败,但工作状态是Gitlab的成功

mnv*_*mnv 2 gitlab docker gitlab-ci gitlab-ci-runner docker-compose

我的Dockerfile:

FROM mm_php:7.1

ADD ./docker/test/source/entrypoint.sh /work/entrypoint.sh
ADD ./docker/wait-for-it.sh /work/wait-for-it.sh
RUN chmod 755 /work/entrypoint.sh \
    && chmod 755 /work/wait-for-it.sh

ENTRYPOINT ["/work/entrypoint.sh"]
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entrypoint.sh:

#!/bin/bash -e

/work/wait-for-it.sh db:5432 -- echo "PostgreSQL started"

./vendor/bin/parallel-phpunit --pu-cmd="./vendor/bin/phpunit -c phpunit-docker.xml" tests
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泊坞窗,compose.yml:

version: '2'
services:

  test:
    build:
      context: .
      args:
        ssh_prv_key: ${ssh_prv_key}
        application_env: ${application_env}
      dockerfile: docker/test/source/Dockerfile
    links:
      - db

  db:
    build:
      context: .
      dockerfile: docker/test/postgres/Dockerfile
    environment:
      PGDATA: /tmp
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.gitlab-ci.yml:

image: docker:latest

services:
  - name: docker:dind
    command: ["--insecure-registry=my.domain:5000 --registry-mirror=http://my.domain"]

before_script:
  - apk add --no-cache py-pip
  - pip install docker-compose
  - mkdir -p ~/.ssh
  - chmod 700 ~/.ssh
  - echo "$SSH_KNOWN_HOSTS" > ~/.ssh/known_hosts
  - chmod 644 ~/.ssh/known_hosts
  - echo "$SSH_PRIVATE_KEY" > ~/.ssh/id_rsa
  - chmod 600 ~/.ssh/id_rsa
  - '[[ -f /.dockerenv ]] && echo -e "Host *\n\tStrictHostKeyChecking no\n\n" > ~/.ssh/config'

test:
  stage: test
  script:
    - export ssh_prv_key="$(cat ~/.ssh/id_rsa)" && export application_env="testing-docker" && docker-compose up --build test
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一切都很好.但是如果测试失败,Gitlab中的工作状态是SUCCESS而不是FAILED.

如果测试失败,如何获得状态FAILED?

UPD

如果我在docker-compose up本地运行,它不会返回错误代码:

$ export ssh_prv_key="$(cat ~/.ssh/id_rsa)" && export application_env="testing-docker" && docker-compose up --build test
Building db
Step 1/2 : FROM mm_postgres:9.6
...
test_1       | FAILURES!
test_1       | Tests: 1, Assertions: 1, Failures: 1.
test_1       | Success: 2 Fail: 2 Error: 0 Skip: 2 Incomplete: 0
mmadmin_test_1 exited with code 1

$ echo $?
0
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Ven*_*ius 6

在我看来,它的测试报告失败,而不必报告docker-compose呼叫返回值的失败.您是否尝试捕获docker-compose测试在本地失败时的返回值?

为了获得docker-compose从一个特定的服务回报退出代码,试试这个:

docker-compose up --exit-code-from=service
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  • 谢谢!我已经更新了我的答案.我还更新了`.gitlab-ci.yml`:`docker-compose up --build --exit-code-from = test test`(添加选项`--exit-code-from`).它现在很好! (2认同)