否定不使用.equalsIgnoreCase()

Question

我试图运行一个do ...虽然条件不满足但由于某种原因我的代码每次都会循环,无论条件的值如何.我已经检查了我的调试器,并且变量的值是正确的,并且根据类似的逻辑满足了循环内的条件.由于某种原因,这!是行不通的.这是我的代码

do
  {
     if(isRaceHorse.equalsIgnoreCase("Y"))
     {
        System.out.print("Please enter the number of races your horse has been in >> ");
        numRaces = input.nextInt();
        input.nextLine();
        System.out.println("Your horse is named " + name + " it is a " + color + " horse born in " + birthYear + " and it has been in " + numRaces + " races.");
     }
     else if(isRaceHorse.equalsIgnoreCase("N"))
     {
        System.out.println("Your horse is named " + name + " it is a " + color + " horse born in " + birthYear + ".");
     }
     else
     {
        System.out.println("Please use Y for yes and N for no.");
        System.out.print("Is your horse a race horse? Enter Y for yes and N for no >> ");
        isRaceHorse = input.nextLine();
     }
  }while(!(isRaceHorse.equalsIgnoreCase("y")) || !(isRaceHorse.equalsIgnoreCase("n")));

任何人都有任何想法,为什么这不给我我想要的东西？

Answer 1

!(isRaceHorse.equalsIgnoreCase("y")) || !(isRaceHorse.equalsIgnoreCase("n"))

在英语中,这意味着只要isRaceHorse不等于"y" 或 isRaceHorse不等于循环,循环就会继续"n".因为它不能等于两者"y"并"n"在同一时间,我敢肯定你想使用&&,而不是:

!isRaceHorse.equalsIgnoreCase("y") && !isRaceHorse.equalsIgnoreCase("n")