在Ms中打印时间差

Question

我在我的python脚本中读取一个日志文件,并且我有一个startTimes和endTimes- 的元组列表

('[19:49:40:680]', '[19:49:49:128]')
('[11:29:10:837]', '[11:29:15:698]')
('[11:30:18:291]', '[11:30:21:025]')
('[11:37:44:293]', '[11:38:02:008]')
('[11:39:14:897]', '[11:39:21:572]')
('[11:42:19:968]', '[11:42:22:036]')
('[11:43:18:887]', '[11:43:19:633]')
('[11:44:26:533]', '[11:49:29:274]')
('[11:55:03:974]', '[11:55:06:372]')
('[11:56:14:096]', '[11:56:14:493]')
('[11:57:08:372]', '[11:57:08:767]')
('[11:59:26:201]', '[11:59:27:438]')

如何以毫秒为单位来区分时间？

Answer 1

>>> import datetime
>>> a = ('[19:49:40:680]', '[19:49:49:128]')
>>> start = datetime.datetime.strptime(a[0][:-1]+"000", "[%H:%M:%S:%f")
>>> end = datetime.datetime.strptime(a[1][:-1]+"000", "[%H:%M:%S:%f")
>>> delta = end-start
>>> ms = delta.seconds*1000 + delta.microseconds/1000
>>> ms
8448.0

如果时钟在午夜环绕,这甚至可以工作:

>>> a = ('[23:59:59:000]','[00:00:01:000]')
>>> # <snip> see above
>>> ms = delta.seconds*1000 + delta.microseconds/1000
>>> ms
2000.0