mcf*_*oft 8 java android gradle classnotfoundexception android-studio
我没有线索(太愚蠢),为什么我的应用程序在运行时没有找到jdbc类:
Exception in thread "main" java.lang.ClassNotFoundException: org.sqlite.JDBC
Run Code Online (Sandbox Code Playgroud)
你有什么提示吗?在此repo中完成简化的用例:https://bitbucket.org/solvapps/jdbcapp
我在我的Androidstudio项目中添加了一个名为"维护"的模块来维护内容,这些内容不应包含在应用程序中.(我已经用另一个应用程序完成了这个).
我保持平衡:
apply plugin: 'java'
dependencies {
compile fileTree(dir: 'libs', include: ['*.jar'])
}
sourceCompatibility = "1.8"
targetCompatibility = "1.8"
repositories {
mavenCentral()
}
dependencies {
compile 'org.xerial:sqlite-jdbc:3.16.1'
compile 'commons-net:commons-net:3.3'
compile 'org.zeroturnaround:zt-zip:1.11'
compile 'org.zeroturnaround:zt-zip:1.11'
compile 'org.apache.commons:commons-lang3:3.5'
}
Run Code Online (Sandbox Code Playgroud)
同步后,我在外部库中看到了jar.
我的代码,不是红色的:
public static void connect(String language, boolean readonly) throws SQLException, ClassNotFoundException, IOException {
// Hole DBPath
String dbpath = Constants.getDbName(language);
Class.forName("org.sqlite.JDBC");
SQLiteConfig config = new SQLiteConfig();
if (readonly){
config.setReadOnly(true);
}else{
config.setReadOnly(false);
}
connection = DriverManager.getConnection("jdbc:sqlite:" + dbpath,config.toProperties());
}
Run Code Online (Sandbox Code Playgroud)
错误:
Exception in thread "main" java.lang.ClassNotFoundException: org.sqlite.JDBC
at java.net.URLClassLoader.findClass(URLClassLoader.java:381)
at java.lang.ClassLoader.loadClass(ClassLoader.java:424)
at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:331)
at java.lang.ClassLoader.loadClass(ClassLoader.java:357)
at java.lang.Class.forName0(Native Method)
at java.lang.Class.forName(Class.java:264)
at solveraapps.maintain.DbService.connect(DbService.java:24)
Run Code Online (Sandbox Code Playgroud)
小智 4
try{
Class.forName("com.mysql.jdbc.Driver");
Connection con;
con=DriverManager.getConnection("jdbc:mysql://localhost:8080/DBName","root","root");
//here DBName is database name, root is username and password
Statement stmt=con.createStatement();
ResultSet rs=stmt.executeQuery("select * from Table_name");
//Table_name is Table Name Which Must Exist IN Your Database
while(rs.next())
System.out.println(rs.getInt(1)+" "+rs.getString(2)+" "+rs.getString(3));
con.close();
}catch(Exception e){ System.out.println(e);}
}
Run Code Online (Sandbox Code Playgroud)
您必须将mysql-connector.jar文件添加到您的库中,您可以从这里下载文件
| 归档时间: |
|
| 查看次数: |
1098 次 |
| 最近记录: |