MySQL'截断错误的INTEGER值'

Question

当我运行以下UPDATE查询时,我得到一个奇怪的'截断错误的INTEGER值'错误:

update tbl
set projectNumber = right(comments, 7)
where createdBy = 'me'
and length(CONVERT(right(comments, 7), SIGNED INTEGER)) = 7 
and CONVERT(right(comments, 7), SIGNED INTEGER) > 0
and CONVERT(right(comments, 7), SIGNED INTEGER) is not null
and createdOn > '2011-01-31 12:00:00'
and projectNumber is null

projectNumber是varchar(10).

当我将其作为直接选择运行时,我没有收到错误,我看到了预期的结果.有任何想法吗？本质上我正在尝试更新projectNumber字段,其中导入的注释中的注释的结尾是7个数字字符(但是projectNumber并不总是 7数字,这就是字段为varchar(10)的原因).

Answer 1

这不是错误.当你要求它将非数字转换为整数时,这是来自CONVERT()的警告;

在控制台中运行这些查询以查看:

mysql> SELECT CONVERT(right('1s23d45678', 7), SIGNED INTEGER);
+-------------------------------------------------+
| CONVERT(right('1s23d45678', 7), SIGNED INTEGER) |
+-------------------------------------------------+
|                                               3 |
+-------------------------------------------------+
1 row in set, 1 warning (0.00 sec)

mysql> SHOW WARNINGS;
+---------+------+----------------------------------------------+
| Level   | Code | Message                                      |
+---------+------+----------------------------------------------+
| Warning | 1292 | Truncated incorrect INTEGER value: '3d45678' |
+---------+------+----------------------------------------------+
1 row in set (0.00 sec)

正如我所说,这是一个警告,而不是错误.您的查询应正确执行更新.

Answer 2

正如其他答案中所述，这是 2019 年的错误，它阻止了查询运行。即使存在无法转换为数字的字符串，也要运行查询，只需使用UPDATE IGNORE.

例如，原始代码的最小版本：

UPDATE IGNORE tbl
SET projectNumber = RIGHT(comments, 7)
WHERE CONVERT(RIGHT(COMMENTS, 7), SIGNED INTEGER) > 0

Answer 3

此警告的另一个常见原因是要转换的字符串中的空格.使用trim()之前convert()摆脱它.