无需用户输入即可向电报组发送消息

Joe*_*Joe 6 python-3.x telegram python-telegram-bot telegram-bot

我正在尝试构建一个机器人,它会在使用 python 的最新新闻中有更新时自动发送消息。以下是我所做的。

companies = {
    "name_1": {
        "rss": "name_1 rss link",
        "link": "name_1 link"
    }
}

import feedparser as fp
import time, telebot
token = <TOKEN>
bot = telebot.TeleBot(token)
LIMIT = 1
while True:
    def get_news():
        count = 1
        news = []
        for company, value in companies.items():
            count = 1
            if 'rss' in value:
                d = fp.parse(value['rss'])
                for entry in d.entries:
                    if hasattr(entry, 'published'):
                        if count > LIMIT:
                            break
                        news.append(entry.link)
                        count = count + 1

        return (news)
    val = get_news()
    time.sleep(10)
    val2 = get_news()
    try:
        if val[0]!=val2[0]:
            bot.send_message(chat_id= "Hardcoded chat_id", text=val2[0])
    except Exception:
        pass
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如何更新我的代码,以便机器人向所有添加它的组发布最新消息?我得到了 chat_id 使用: bot.get_updates()[-1].message.chat.id 任何关于如何自动执行此操作的建议?

576*_*76i 7

使用python-telegram-bot api,您可以发送这样的消息

bot.send_message(id, text='Message')
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你需要“bot”和“id”

我将这些保存在名为“mybots”的字典中,当人们第一次与机器人交互/或以后与机器人进行通信时,我会填写/更新该词典。可以腌制这本字典以保持其持久性。

mybots = {}

def start(bot, update):
    """Send a message when the command /start is issued."""
      mybots[update.message.chat_id] = bot
      update.message.reply_text('Hello{}!'.format(
           update.effective_chat.first_name))

def send_later():
    for id, bot in mybots.items():
        bot.send_message(id, text='Beep!')
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Sum*_*ran 5

简而言之,您可以用来sendMessage()向特定组或用户发送消息。

bot.sendMessage(chat_id=chat_id, text=msg)
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完整的代码,

import telegram


#token that can be generated talking with @BotFather on telegram
my_token = ''

def send(msg, chat_id, token=my_token):
    """
    Send a message to a telegram user or group specified on chatId
    chat_id must be a number!
    """
    bot = telegram.Bot(token=token)
    bot.sendMessage(chat_id=chat_id, text=msg)
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