Raf*_* K. 6 fetch node.js fetch-mock
这是代码片段:
var fetch = require("node-fetch");
var fetchMock = require("fetch-mock");
function setupMockBlockChainExplorer() {
fetchMock.mock("https://cardanoexplorer.com/api/addresses/summary/DdzFFzCqrhsmagp4fDZpcY9UaBJk4Z8GaDfxqMCSwxPs3PnVoXmJWUZcgAxw3diCHVYauontEfk7YGeAu2LvAwq3aG2XQ8Mtsz7Vc8LA", {
"status" : 200,
"body" : "override"
});
}
async function makeRequest(url, method = "get", body = null, headers = null) {
const res = await fetch(url, {
method: method,
headers: headers,
body: body,
});
return res.json()
};
setupMockBlockChainExplorer();
var req = makeRequest("https://cardanoexplorer.com/api/addresses/summary/DdzFFzCqrhsmagp4fDZpcY9UaBJk4Z8GaDfxqMCSwxPs3PnVoXmJWUZcgAxw3diCHVYauontEfk7YGeAu2LvAwq3aG2XQ8Mtsz7Vc8LA");
// I would expect it to print "override" but it prints the http response from the real request instead
req.then(console.log)
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因此,正如您在上面的代码中看到的那样,我试图覆盖HTTP请求,但是我仍然使用fetch来访问真实的URL。我已经阅读了fetch-mock文档(http://www.wheresrhys.co.uk/fetch-mock/installation.html),并且还尝试过这样的配置:
fetchMock.config = Object.assign(fetchMock.config, {
"fetch": fetch
});
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但没有运气。我究竟做错了什么?
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