我知道有办法做到这一点,但我一直在撞墙试图解决这个问题.这很好用:
private GenericRecord CreateGeneric(GenericRecord g, Member m)
{
g.Member = m;
return g;
}
public IList<GenericRecord> ReportFromDatabase(DateTime startDate, DateTime endDate)
{
List<GenericRecord> returnRecords = new List<GenericRecord>();
returnRecords.AddRange(from r in pjRepository.Records
join m in memberRepository.Members on r.SID equals m.MemberId.ToString()
where r.TransactionDate >= startDate && r.TransactionDate <= endDate
select CreateGeneric((GenericRecord)r, m));
return returnRecords;
}
Run Code Online (Sandbox Code Playgroud)
但我知道有一种方法可以在没有CreateGeneric函数的情况下完成它.如何内联选择委托功能?
returnRecords.AddRange(from r in pjRepository.Records
join m in memberRepository.Members on r.SID equals m.MemberId.ToString()
where r.TransactionDate >= startDate && r.TransactionDate <= endDate
select (delegate
{
GenericRecord g = (GenericRecord)r;
g.Member = m;
return g;
}));
Run Code Online (Sandbox Code Playgroud)
这给了我这个例外:
The type of the expression in the select clause is incorrect. Type inference failed in the call to 'Select'.
Run Code Online (Sandbox Code Playgroud)
编辑:另一次尝试失败
returnRecords.AddRange((from r in pjRepository.Records
join m in memberRepository.Members on r.SID equals m.MemberId.ToString()
where r.TransactionDate >= startDate && r.TransactionDate <= endDate
select new { r, m }).Select(x =>
{
GenericRecord g = (GenericRecord)x.r;
g.Member = x.m;
return g;
}));
Run Code Online (Sandbox Code Playgroud)
这给了我:
具有语句主体的lambda表达式无法转换为表达式树.
Kei*_*thS 12
尝试:
returnRecords.AddRange((from r in pjRepository.Records
join m in memberRepository.Members on r.SID equals m.MemberId.ToString()
where r.TransactionDate >= startDate && r.TransactionDate <= endDate
select new { r, m }).AsEnumerable().Select(x =>
{
GenericRecord g = (GenericRecord)x.r;
g.Member = x.m;
return g;
}));
Run Code Online (Sandbox Code Playgroud)
关键不同的是AsEnumerable()函数.这需要一个IQueryable并返回一个IEnumerable,它在幕后迫使Linq提供者对表达式树进行评估.这可以防止Linq库尝试将第二个Select的lambda转换为表达式树的一部分(它说它不能); 第二个Select将通过评估IQueryable表达式树对生成的实际内存集合执行转换.由于您需要在语句结束之前评估查询(因此可以将所有元素添加到returnRecords),因此应该没有显着的性能差异.