Jer*_*emy 2 javascript typescript apollo graphql
我正在尝试通过单击按钮将新数据提交到本地 graphQL API,但出现错误:错误错误:未捕获(承诺中):错误:网络错误:http://localhost:4000/的 Http 失败响应graphql:400 错误请求。
这个想法是,当您按下按钮时,就会提交新数据
<button type="submit" (click)="onSubmit()" [disabled]="!personForm.valid" id="buttonSubmit" mat-raised-button color="accent"class="floated">Send</button>
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onSubmit 函数调用突变
onSubmit()
{
let id = 5;
let vorname = 'user';
let name = 'name';
let email = 'testt@hotmail.com';
let status = 'true';
let activity = 'Office';
this.apollo.mutate<CreateUserMutationResponse>({
mutation: CREATE_USER_MUTATION,
variables: {
id: id,
vorname: vorname,
name: name,
email: email,
status: status,
activity: activity
}
}).subscribe((response) => {
});
console.log('submitted');
}
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我的 types.ts 中的突变看起来像这样
export const CREATE_USER_MUTATION = gql`
mutation CreateUserMutation($id: ID!, $vorname: String!, $name: String!, $email: String!, $status: String!, $activity: String) {
createUser(id: $id,vorname: $vorname, name: $name, email: $email, status: $status, activity: $activity) {
id
vorname
name
email
status
activity
}
}
`;
export interface CreateUserMutationResponse {
createUser: String;
}
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小智 5
当我发现你的问题时,我实际上也遇到了同样的问题。有关此问题的文档很难获得,但是这个示例告诉我如何解决这个问题。在我用try catch 语句包围突变后,它对我有用。我确信这样的事情也会为您解决:
onSubmit() {
[...]
try {
this.$apollo.mutate <CreateUserMutationResponse>({
mutation: CREATE_USER_MUTATION,
variables: {
id: id,
vorname: vorname,
name: name,
email: email,
status: status,
activity: activity
}
}).subscribe((response) => { });
} catch (e) {
console.error(e);
}
console.log('submitted');
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此页面还帮助我首先设置了突变(看来您已经做得正确了)。