GraphQL + Apollo 错误:未捕获(承诺)

Jer*_*emy 2 javascript typescript apollo graphql

我正在尝试通过单击按钮将新数据提交到本地 graphQL API,但出现错误:错误错误:未捕获(承诺中):错误:网络错误:http://localhost:4000/的 Http 失败响应graphql:400 错误请求。

这个想法是,当您按下按钮时,就会提交新数据

  <button type="submit" (click)="onSubmit()" [disabled]="!personForm.valid" id="buttonSubmit" mat-raised-button color="accent"class="floated">Send</button>
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onSubmit 函数调用突变

  onSubmit() 
  {
    let id = 5;
    let vorname = 'user';
    let name =  'name';
    let email =  'testt@hotmail.com';
    let status =  'true';
    let activity =  'Office';

    this.apollo.mutate<CreateUserMutationResponse>({
      mutation: CREATE_USER_MUTATION,
      variables: {
        id: id,
        vorname: vorname,
        name: name,
        email: email,
        status: status,
        activity: activity
      }
    }).subscribe((response) => {

    });

    console.log('submitted');

  }
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我的 types.ts 中的突变看起来像这样

export const CREATE_USER_MUTATION = gql`
  mutation CreateUserMutation($id: ID!, $vorname: String!, $name: String!, $email: String!, $status: String!, $activity: String) {
    createUser(id: $id,vorname: $vorname, name: $name, email: $email, status: $status, activity: $activity) {
      id
      vorname
      name
      email
      status
      activity
    }
  }
`;

export interface CreateUserMutationResponse {
  createUser: String;
}
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小智 5

当我发现你的问题时,我实际上也遇到了同样的问题。有关此问题的文档很难获得,但是这个示例告诉我如何解决这个问题。在我用try catch 语句包围突变后,它对我有用。我确信这样的事情也会为您解决:

onSubmit() {

  [...]

  try {
    this.$apollo.mutate <CreateUserMutationResponse>({
      mutation: CREATE_USER_MUTATION,
      variables: {
        id: id,
        vorname: vorname,
        name: name,
        email: email,
        status: status,
        activity: activity
       }
     }).subscribe((response) => { });
   } catch (e) {
      console.error(e);
   }

  console.log('submitted');
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此页面还帮助我首先设置了突变(看来您已经做得正确了)。