从pytest_generate_tests中排除测试

Question

我有几个用pytest编写的测试文件:

test_foo.py:

class TestFoo:
    def test_foo_one(self, current_locale):
        # some actions with locale
        # assert

    def test_foo_two(self, current_locale):
        # some actions with locale
        # assert

test_bar.py:

class TestBar:
    def test_bar_one(self, current_locale):
        # some actions with locale
        # assert

    def test_bar_two(self, current_locale):
        # some actions with locale
        # assert

和conftest.py:

locales = ["da-DK", "de-DE", "en-GB", "en-US", "es-AR", "es-CO", "es-ES", "es-MX", "fi-FI"]

def pytest_generate_tests(metafunc):
    metafunc.parametrize('current_locale', locales, scope='session')

它允许为每个区域设置运行测试.

现在,我想创建一个我不需要locales的测试,它必须只运行一次. test_without_locales.py:

class TestNoLocales:
    def test_no_locales(self):
        # some actions with locale
        # assert

它引发了一个错误:ValueError:不使用参数'current_locale'

如何在不使用current_locales的情况下编写测试？

Answer 1

您只是错过了对每个测试用例中包含的灯具的检查.

locales = ["da-DK", "de-DE", "en-GB", "en-US", "es-AR", "es-CO", "es-ES", "es-MX", "fi-FI"]

def pytest_generate_tests(metafunc):
    if 'current_locale' in metafunc.fixturenames:
        metafunc.parametrize('current_locale', locales, scope='session')

或者你可以通过这样做使它更加光滑:

params = {"current_locale": ["da-DK", "de-DE", "en-GB", "en-US", "es-AR", "es-CO", "es-ES", "es-MX", "fi-FI"]}
def pytest_generate_tests(metafunc):
    for k,v in params:
        if k in metafunc.fixturenames:
            metafunc.parametrize(k, v, scope='session')

这是因为pytest按顺序加载每个fixture,所以你可以逐个注入它们(如果你有多个param,那就是)

至于排除测试运行,@ pytest.mark.skip()装饰器为你.