sir*_*sek 4 php orm model kohana kohana-3
我有这两个模型:
class Model_user extends ORM {
protected $_has_many = array('credits', array('model'=>'credit', 'foreign_key'=>'user'));
}
class Model_credit extends ORM {
protected $_belongs_to = array('user', array('model'=>'user', 'foreign_key'=>'user'));
protected $_tb = 'credits';
protected $_pk = 'id';
// method to be implemented
public function total() {
return $total_credits_available;
}
}
// accessing the 'total' method
$user = ORM::factory('user', 1);
$total_credits = $user->credits->total();
问题是如何实现'total'方法,它具有以下特点:
return DB::select(array(DB::expr('SUM(qty * sign)'), 'total'))
->from($this->_tb)
->where('user', '=', $user_id)
->execute()
->total;
该方法计算用户的信用(可以是+信用和 - 信用)并返回可用信用总额.只要我使用ORM :: factory方法创建用户对象,我就想以这样的方式实现'total'方法,它使用加载的资源而不是运行新的查询(我写了上面的查询来演示业务逻辑).
有什么建议?:)
<?php
class Model_user extends ORM {
protected static $_totals = array();
protected $_has_many = array('credits', array('model'=>'credit', 'foreign_key'=>'user'));
public function total()
{
$total = Arr::get(Model_User::$_totals, $this->id, FALSE);
if ($total !== FALSE)
return $total;
return Model_User::$_totals[$this->id] = $this->credits
->select(array(DB::expr('SUM(qty * sign)'), 'total'))
->find()
->total;
}
}
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