将 INTERVAL DAY 转换为 SECOND

Question

我想使用间隔数据类型获得更具可读性的值。

select cast(last_run_duration as INTERVAL DAY TO SECOND(0))
from dba_scheduler_jobs
order by 1 desc;

查询结果是这样的；

+00 00:00:04.630530
+00 00:00:01.352359
+00 00:00:00.737282
+00 00:00:00.594381
+00 00:00:00.432710

我想要的是这个。只获取小时：分钟：秒；

 00:00:04
 00:00:01
 00:00:00
 00:00:00
 00:00:00

last_run_duration 列的数据类型是 INTERVAL DAY(9) TO SECOND(6)

Answer 1

INTERAVL DAY TO SECOND有固定的输出格式，TO_CHAR不起作用。

EXTRACT按照 Edumelzer 的建议使用

select lpad(extract(hour from last_run_duration),2,'0')||':'||
       lpad(extract(minute from last_run_duration),2,'0')||':'||
       lpad(round(extract(second from last_run_duration)),2,'0') as duration
  from dba_scheduler_jobs
 order by 1 desc;

或者使用像这样的子字符串

select 
REGEXP_SUBSTR(last_run_duration, '\d{2}:\d{2}:\d{2}')
from from dba_scheduler_jobs;