模型项的类型为CookMeIndexViewModel,但需要IEnumerable <CookMeIndexViewModel>类型的模型项

Question

我跟随音乐商店的例子来尝试学习ASP.NET MVC.我正在创建一本食谱应用程序.

我创建了我的viewmodel,如下所示:

namespace CookMe_MVC.ViewModels
{
    public class CookMeIndexViewModel
    {
        public int NumberOfReceipes { get; set; }
        public List<string> ReceipeName { get; set; }
    }
}

我的控制器看起来像这样

public ActionResult Index()
    {
        var meals= new List<string> { "Dinner 1", "Dinner 2", "3rd not sure" };
       //create the view model
        var viewModel = new CookMeIndexViewModel
        {
            NumberOfReceipes = meals.Count(),
            ReceipeName = meals
        };
        return View(viewModel);
    }

最后,我的观点看起来像这样

 @model IEnumerable<CookMe_MVC.ViewModels.CookMeIndexViewModel>

@{
    ViewBag.Title = "Index";
}

<h2>Index</h2>

<p>
    @Html.ActionLink("Create New", "Create")
</p>
<table>
    <tr>
        <th></th>
        <th>
            Meals
        </th>
    </tr>

@foreach (var item in Model) {
    <tr>
        <td>
            @Html.ActionLink("Edit", "Edit", new { /* id=item.PrimaryKey */ }) |
            @Html.ActionLink("Details", "Details", new { /* id=item.PrimaryKey */ }) |
            @Html.ActionLink("Delete", "Delete", new { /* id=item.PrimaryKey */ })
        </td>
        <td>
            @item.ReceipeName
        </td>
    </tr>
}

</table>

我收到这个错误.

传递到字典中的模型项是类型CookMeIndexViewModel,但此字典需要类型的模型项IEnumerable<CookMeIndexViewModel>.

我跟着这个例子.我看不出我做错了什么.我应该将我的viewmodel作为通用列表返回吗？

Answer 1

在您使用的视图中@model IEnumerable<CookMe_MVC.ViewModels.CookMeIndexViewModel>,表示View预期的模型类型为CookMeIndexViewModel的IEnumerable类型.

但是在控制器中,您将CookMeIndexViewModel类型的对象作为模型传递,return View(viewModel);因此会出错.

要么改变视图 @model CookMe_MVC.ViewModels.CookMeIndexViewModel

或者将IEnumerable的CookMeIndexViewModel作为模型传递给控制器​​中的视图,如下所示:

public ActionResult Index()
{
        var meals= new List<string> { "Dinner 1", "Dinner 2", "3rd not sure" };
     //create the view model
        var viewModel = new CookMeIndexViewModel
        {
                NumberOfReceipes = meals.Count(),
                ReceipeName = meals
        };
        List<CookMeIndexViewModel> viewModelList = new List<CookMeIndexViewModel>();
        viewModelList.Add(viewModel);
        return View(viewModelList);
}