pas*_*asi 9 r lubridate dplyr tidyverse tibble
我正在尝试找到重叠的间隔,并决定将间隔数据加入到自身中,dplyr::left_join()
以便我可以将间隔与lubridate::int_overlaps()
每个其他间隔进行比较.
这是我期望left_join()
的表现方式.两个tibbles具有三行交叉以形成tibble与9行:
library(tidyverse)
tibble(a = rep("a", 3), b = rep(1, 3)) %>%
left_join(tibble(a = rep("a", 3), c = rep(2, 3)))
Joining, by = "a"
# A tibble: 9 x 3
a b c
<chr> <dbl> <dbl>
1 a 1 2
2 a 1 2
3 a 1 2
4 a 1 2
5 a 1 2
6 a 1 2
7 a 1 2
8 a 1 2
9 a 1 2
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以下是相同代码对间隔的行为方式.我得到九行,但行不像上面那样交叉:
tibble(a = rep("a", 3), b = rep(make_date(2001) %--% make_date(2002), 3)) %>%
left_join(tibble(a = rep("a", 3), c = rep(make_date(2002) %--% make_date(2003))))
Joining, by = "a"
# A tibble: 9 x 3
a b c
<chr> <S4: Interval> <S4: Interval>
1 a 2001-01-01 UTC--2002-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
2 a 2001-01-01 UTC--2002-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
3 a 2001-01-01 UTC--2002-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
4 a NA--NA NA--NA
5 a NA--NA NA--NA
6 a NA--NA NA--NA
7 a NA--NA NA--NA
8 a NA--NA NA--NA
9 a NA--NA NA--NA
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我认为这是意料之外的,但我可能会遗漏一些东西?或者这是一个错误?
错误
该对象仍包含相关信息:
res <- tibble(a = rep("a", 3), b = rep(make_date(2001) %--% make_date(2002), 3)) %>%
left_join(tibble(a = rep("a", 3), c = rep(make_date(2002) %--% make_date(2003))))
print.data.frame(res)
# a b c
# 1 a 2001-01-01 UTC--2002-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
# 2 a 2001-01-01 UTC--2002-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
# 3 a 2001-01-01 UTC--2002-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
# 4 a 2001-01-01 UTC--2002-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
# 5 a 2001-01-01 UTC--2002-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
# 6 a 2001-01-01 UTC--2002-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
# 7 a 2001-01-01 UTC--2002-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
# 8 a 2001-01-01 UTC--2002-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
# 9 a 2001-01-01 UTC--2002-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
res$c
# [1] 2002-01-01 UTC--2003-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
# [5] 2002-01-01 UTC--2003-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
# [9] 2002-01-01 UTC--2003-01-01 UTC
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但是当通过索引进行子集化时,它不再起作用:
res_df <- as.data.frame(res)
head(res_df)
a b c
1 a 2001-01-01 UTC--2002-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
2 a 2001-01-01 UTC--2002-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
3 a 2001-01-01 UTC--2002-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
4 a NA--NA NA--NA
5 a NA--NA NA--NA
6 a NA--NA NA--NA
res_df[4,"c"]
[1] NA--NA
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并tibble:::print.tbl
利用head
.这就是为什么问题立即可见,tibbles
而不是data.frames
.
打字str(res$b)
我们看到start
9个data
值只有3 个值.
如果我们这样做:
res_df$b@start <- rep(res_df$b@start,3)
res_df$c@start <- rep(res_df$c@start,3)
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现在打印好了:
a b c
1 a 2001-01-01 UTC--2002-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
2 a 2001-01-01 UTC--2002-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
3 a 2001-01-01 UTC--2002-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
4 a 2001-01-01 UTC--2002-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
5 a 2001-01-01 UTC--2002-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
6 a 2001-01-01 UTC--2002-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
7 a 2001-01-01 UTC--2002-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
8 a 2001-01-01 UTC--2002-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
9 a 2001-01-01 UTC--2002-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
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解决方案
我们已经看到这as.data.frame
还不够,left_join
是功能搞乱了,merge
改为使用:
res <- tibble(a = rep("a", 3), b = rep(make_date(2001) %--% make_date(2002), 3)) %>%
merge(tibble(a = rep("a", 3), c = rep(make_date(2002) %--% make_date(2003))),
all.x=TRUE)
head(res)
# a b c
# 1 a 2001-01-01 UTC--2002-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
# 2 a 2001-01-01 UTC--2002-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
# 3 a 2001-01-01 UTC--2002-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
# 4 a 2001-01-01 UTC--2002-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
# 5 a 2001-01-01 UTC--2002-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
# 6 a 2001-01-01 UTC--2002-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
res[4,"c"]
#[1] 2002-01-01 UTC--2003-01-01 UTC
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我在这里报告了这个问题
这个问题不再存在,因为这个问题已经关闭并且相关功能已实现。如果您现在使用更新的包运行代码,它将起作用。
library(lubridate)
library(tidyverse)
tibble(a = rep("a", 3), b = rep(make_date(2001) %--% make_date(2002), 3)) %>%
left_join(tibble(a = rep("a", 3), c = rep(make_date(2002) %--% make_date(2003))))
#> Joining, by = "a"
#> # A tibble: 9 x 3
#> a b c
#> <chr> <Interval> <Interval>
#> 1 a 2001-01-01 UTC--2002-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
#> 2 a 2001-01-01 UTC--2002-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
#> 3 a 2001-01-01 UTC--2002-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
#> 4 a 2001-01-01 UTC--2002-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
#> 5 a 2001-01-01 UTC--2002-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
#> 6 a 2001-01-01 UTC--2002-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
#> 7 a 2001-01-01 UTC--2002-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
#> 8 a 2001-01-01 UTC--2002-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
#> 9 a 2001-01-01 UTC--2002-01-01 UTC 2002-01-01 UTC--2003-01-01 UTC
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由reprex 包(v0.3.0)于 2019-06-07 创建