我得到了这个杰森:
{
"CountriesAndCities": [
{
"CountryId": 2,
"CountryName": "Chile",
"CountryISOA3": "CHL",
"Cities": [
{
"CityId": 26,
"CityName": "Gran Santiago",
"Country": null
},
{
"CityId": 27,
"CityName": "Gran Concepción",
"Country": null
}
]
}
]
}
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如您所见,它是一个对象列表,这些对象嵌套了另一个列表。
我有以下模型:
public class City
{
public int CityId { get; set; }
public string CityName { get; set; }
public Country Country { get; set; }
}
public class Country
{
public int CountryId { get; set; }
public string CountryName { get; set; }
public string CountryISOA3 { get; set; }
public ICollection<City> Cities { get; set; }
}
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现在,这可以解决问题:
public ICollection<Country> Countries { get; set; }
public RegionViewModel()
{
// Pidiendo las ciudades al backend.
S3EWebApi webApi = new S3EWebApi();
HttpResponseMessage response = webApi.Get("/api/Benefits/GetCountriesAndCities");
string jsonResponseString = response.Content.ReadAsStringAsync().Result;
JObject jsonResponse = JsonConvert.DeserializeObject<JObject>(jsonResponseString);
string countriesAndCitiesJSon = jsonResponse["CountriesAndCities"].ToString();
Countries = JsonConvert.DeserializeObject<List<Country>>(countriesAndCitiesJSon);
}
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但是我不知道,我认为这离优雅还差得远。有更好的方法吗?谢谢。:)
一般来说,您永远不需要反序列化两次。最简单的解决方案是创建一个类来表示 JSON 的最外层部分,然后反序列化为@Alex Wiese's answer 所示。
如果你想在没有根类的情况下反序列化,那么你可以ToObject<T>()在反序列化到JObject.
JObject jsonResponse = JsonConvert.DeserializeObject<JObject>(jsonResponseString);
Countries = jsonResponse["CountriesAndCities"].ToObject<List<Country>>();
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为响应创建一个包装类。
public class CountriesAndCitiesResponse
{
public List<Country> CountriesAndCities { get; set; }
}
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然后像这样使用它:
public RegionViewModel()
{
// Pidiendo las ciudades al backend.
S3EWebApi webApi = new S3EWebApi();
HttpResponseMessage response = webApi.Get("/api/Benefits/GetCountriesAndCities");
string jsonResponseString = response.Content.ReadAsStringAsync().Result;
CountriesAndCitiesResponse response = JsonConvert.DeserializeObject<CountriesAndCitiesResponse>(jsonResponseString);
Countries = response.CountriesAndCities;
}
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此外,您应该重新考虑async在构造函数中调用方法(它可能导致死锁)。您可能会考虑在async Task Load()方法中进行调用,并在调用构造函数后调用该方法。