Nodejs:使用sinon和async/await进行测试

Question

无法使用sinon和async/await运行此测试.这是我正在做的一个例子:

// in file funcs
async function funcA(id) {
    let url = getRoute53() + id
    return await funcB(url);
}

async function funcB(url) {
    // empty function
}

而且测试:

let funcs = require('./funcs');

...

// describe
let stubRoute53 = null;
let stubFuncB = null;
let route53 = 'https://sample-route53.com/' 
let id = '1234'
let url = route53 + id;

beforeEach(() => {
    stubRoute53 = sinon.stub(funcs, 'getRoute53').returns(route53);
    stubFuncB = sinon.stub(funcs, 'funcB').resolves('Not interested in the output');
})

afterEach(() => {
    stubRoute53.restore();
    stubFuncB.restore();
})

it ('Should create a valid url and test to see if funcB was called with the correct args', async () => {
    await funcs.funcA(id);
    sinon.assert.calledWith(stubFuncB, url)
})

通过console.log我已经验证funcA正在生成正确的URL,但是,我收到了错误AssertError: expected funcB to be called with arguments.当我尝试调用stubFuncB.getCall(0).args它时打印出null.所以也许是我对async/await缺乏了解,但我无法弄清楚为什么url没有被传递给那个函数调用.

谢谢

Answer 1

我认为你的funcs声明不正确.Sinon无法存根getRoute53并funcB调用内部funcA试试这个:

funcs.js

const funcs = {
  getRoute53: () => 'not important',
  funcA: async (id) => {
    let url = funcs.getRoute53() + id
    return await funcs.funcB(url);
  },
  funcB: async () => null
}

module.exports = funcs

tests.js

describe('funcs', () => {
  let sandbox = null;

  beforeEach(() => {
    sandbox = sinon.createSandbox();
  })

  afterEach(() => {
    sandbox.restore()
  })


  it ('Should create a valid url and test to see if funcB was called with the correct args', async () => {
    const stubRoute53 = sandbox.stub(funcs, 'getRoute53').returns('https://sample-route53.com/');
    const stubFuncB = sandbox.stub(funcs, 'funcB').resolves('Not interested in the output');

    await funcs.funcA('1234');

    sinon.assert.calledWith(stubFuncB, 'https://sample-route53.com/1234')
  })
})

PS此外,使用沙箱.清理存根更容易