Fed*_* E. 8 typescript angular
大家好,这让我疯了.我尝试了我能在网上找到的所有修复程序,似乎没有任何工作.
我从DB加载base64图像信息,返回base64编码的图像,如下所示:
/9j/4AAQSkZJRgABAQEBLAEsAAD/4UHuRXhpZgAATU0AKgAAAAgABgEaAAUAAAABAAAAVgEbAAUAAAABAAAAXgEoAAMAAAABAAIAAAITAAMAAAABAAEAAIdpAAQAAAABAAAIcuocAAcAAAgMAAAAZgAAEOQAAAEsAAAAAQAAASwAAAABHOoAAAAIAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA...
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然后在我的TS文件中,我有以下功能:
photo_url(data:string){
this.user_photo = this.domSanitizer.bypassSecurityTrustResourceUrl('data:image/jpeg;base64,' + data).toString();
}
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我的HTML文件如下所示:
<img [src]="user_photo ? user_photo : 'assets/img/default.png'">
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但是我收到以下错误,图像没有显示:
WARNING: sanitizing unsafe URL value SafeValue must use [property]=binding: data:image/jpeg;base64,/9j/4AAQSkZJRgABAQEBLAEsAAD/4UHuRXhpZgAATU0AKgAAAAgABgEaAAUAAAABAAAAVgEbAAUAAAABAAAAXgEoAAMAAAABAAIAAAITAAMAAAABAAEAAIdpAAQAAAABAAAIcuocAAcAAAgMAAAAZgAAEOQAAAEsAAAAAQAAASwAAAABHOoAAAAIAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA...
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错误说sanitizer应该使用属性绑定,它是,但它仍然显示错误和图像不显示.
我在这里错过了什么吗?
谢谢!
使用时,.toString您将设置user_photo为字符串而不是SafeResourceUrl根据需要。
实际上,只需删除.toString()将使此工作正常。否则,您实际上只是在撤消DomSanitizer的工作。
user_photo: SafeResourceUrl;
photo_url(data: string){
this.user_photo = this.domSanitizer.bypassSecurityTrustResourceUrl(
'data:image/jpeg;base64,' + data);
}
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