在django rest框架中从序列化器发送自定义错误响应?

Sal*_*med 2 django django-models python-3.x django-serializer django-rest-framework

我想从序列化程序创建一个自定义响应创建视图到我的应用程序的前端.我尝试了休息框架响应教程,但它不起作用.我的代码是:

class UserSerializer(serializers.ModelSerializer):
"""Serializer to serialize user model object"""

    class Meta:
        model = User
        fields = ('id', 'username', 'password', 'first_name', 'last_name')
        extra_kwargs = {'password': {'write_only': True}}

    def create(self, validated_data):
        """create a new user"""

        firstname = self.initial_data['first_name']
        lastname = self.initial_data['last_name']
        fullname = str(firstname) +" "+ str(lastname)
        email = self.initial_data['username'].lower()

        try:
           customer = User.create(
                name=fullname,
                email=email)

        except Error as e:
            error = {'message': e._message or 'Unknown error'}
            return Response(error,status=status.HTTP_400_BAD_REQUEST)
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小智 9

serializers.py

class UserSerializer(serializers.ModelSerializer):
"""Serializer to serialize user model object"""

    class Meta:
        model = User
        fields = ('id', 'username', 'password', 'first_name', 'last_name')
        extra_kwargs = {'password': {'write_only': True}}

    def create(self, validated_data):
        """create a new user"""

        firstname = validated_data['first_name']
        lastname = validated_data['last_name']
        fullname = str(firstname) +" "+ str(lastname)
        email = validated_data['username'].lower()

        try:
           customer = User.objects.create(
                name=fullname,
                email=email)
           return customer

        except Exception as e:
            error = {'message': ",".join(e.args) if len(e.args) > 0 else 'Unknown Error'}
            raise serializers.ValidationError(error)
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