如何处理多个社交登录帐户迅速将登录重定向回应用程序？

Question

我正在制作一个应用程序，允许用户从不同的平台（例如google，Facebook，twitter等）登录。在应用程序委托中，我们必须为每个平台实现一个功能application：openURL：options:。目前，我的功能如下所示。

func application(_ app: UIApplication, open url: URL, options: [UIApplicationOpenURLOptionsKey : Any] = [:]) -> Bool {

    // Todo handle based on the the arguments and return the bool value to be checked on iPHONE with facebook, google and twitter app
    let handled = FBSDKApplicationDelegate.sharedInstance().application(app, open: url, sourceApplication: options[UIApplicationOpenURLOptionsKey.sourceApplication] as! String!, annotation: options[UIApplicationOpenURLOptionsKey.annotation])

    GIDSignIn.sharedInstance().handle(url, sourceApplication:options[UIApplicationOpenURLOptionsKey.sourceApplication] as? String, annotation: [:])

    Twitter.sharedInstance().application(app, open: url, options: options)

    return handled
}

如上所示，我返回的是Facebook的重定向句柄结果。Google和Twitter也返回布尔值。返回上述功能的Facebook，google和twitter的句柄布尔值的最安全正确方法是什么？

Answer 1

试试这个方法

func application(_ app: UIApplication, open url: URL, options: [UIApplicationOpenURLOptionsKey : Any] = [:]) -> Bool {

     let facebookDidHandle = FBSDKApplicationDelegate.sharedInstance().application(app, open: url, sourceApplication: options[UIApplicationOpenURLOptionsKey.sourceApplication] as! String!, annotation: options[UIApplicationOpenURLOptionsKey.annotation])

     let googleDidhandle = GIDSignIn.sharedInstance().handle(url, sourceApplication:options[UIApplicationOpenURLOptionsKey.sourceApplication] as? String, annotation: [:])

     let twitterDidHandle = Twitter.sharedInstance().application(app, open: url, options: options)


     return googleDidHandle || facebookDidHandle || twitterDidHandle
}