Man*_*kar 15 php inheritance class private-members
class Person {
public $name;
private $age; //private access
}
class Employee extends Person{
public $id;
public $salary; //class property
}
$emp = new Employee();
$emp->name="ABCD";
$emp->age = 30;
$emp->id=101;
$emp->salary=20000;
echo "<br/> Name : ".$emp->name;
echo "<br/> Age : ".$emp->age;
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在此代码中,子类变量$emp可以Person直接访问父类的私有成员.这不违反私人访问规则吗?
使用父类变量时会出错,但是使用子类变量!! 有谁能解释为什么?
Iva*_*ita 19
TLDR;
$emp->age = 30不调用父私有成员age,它age动态创建新的子对象属性.
说明
看起来像一个bug,不是吗?首先,让我们注释掉父母的私人成员:
<?php
class Person {
// private $age;
}
class Employee extends Person {
}
$emp = new Employee();
$emp->age = 10;
echo $emp->age . "\n";
//out: 10
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在该行中,$emp->age = 10我们创建了$emp对象的新属性age并为其赋值10.
当您将父成员定义为私有成员时,子成员根本不会看到此成员:
<?php
class Person {
private $age;
function __construct() {
$this->age = 30;
}
public function printAge()
{
echo sprintf("Parent::age = %s\n", $this->age);
}
}
class Employee extends Person {
private $age;
function __construct() {
parent::__construct();
$this->age = 10;
}
public function printAge()
{
echo sprintf("Employee::age = %s\n", $this->age);
parent::printAge();
}
}
$emp = new Employee();
$emp->printAge();
//out:
//Employee::age = 10
//Parent::age = 30
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