适用于Firebase HTTP超时的云功能

Gio*_*usa 5 javascript firebase google-cloud-functions

我跟这个很亲密.

我编写了一个Cloud Function,它将从Azure令牌发送的信息转换为自定义的Firebase令牌并将此令牌发送回客户端.

令牌已正确创建,但不会在我的HTTP请求中返回.

很遗憾,我的Firebase应用会导致超时.

函数执行花了60002毫秒,完成状态:'超时'

我无法真正理解为什么会这样,因此这篇文章.我的代码有问题,还是我调用HTTP请求错了?

这是我从Firebase Functions控制台获得的日志.

Firebase功能日志

这是我的代码

// Create a Firebase token from any UID
exports.createFirebaseToken = functions.https.onRequest((req, res) => {

  // The UID and other things we'll assign to the user.
  const uid = req.body.uid;
  const additionalClaims = {
    name: req.body.name,
    email: req.body.email
  };

  // Create or update the user account.
  const userCreationTask = admin.auth().updateUser(uid, additionalClaims).catch(error => {

    // If user does not exists we create it.
    if (error.code === 'auth/user-not-found') {
      console.log(`Created user with UID:${uid}, Name: ${additionalClaims.name} and e-mail: ${additionalClaims.email}`);
      return admin.auth().createUser({
        uid: uid,
        displayName: displayName,
        email: email,
      });
    }
    throw error;
    console.log('Error!');
  });

  // Wait for all async tasks to complete, then generate and return a custom auth token.
  return Promise.all([userCreationTask]).then(() => {
    console.log('Function create token triggered');
    // Create a Firebase custom auth token.
    return admin.auth().createCustomToken(uid, additionalClaims).then((token) => {
      console.log('Created Custom token for UID "', uid, '" Token:', token);
      return token;
    });
  });
});
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当我发出这个HTTP请求时,我发送的所有内容都是JSON这样的:

parameters = [
    "uid" : id,
    "email" : mail,
    "name" : name
]
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Gri*_*orr 9

通过HTTP请求触发云功能需要通过与他们结束而终止send(),redirect()或者end(),否则他们将继续运行,并达到超时.

HTTP触发器文档终止HTTP功能部分:

最后总是与HTTP功能send(),redirect()end().否则,您的功能可能会继续运行并被系统强行终止.另请参阅同步,异步和承诺.

在使用Node.js moment模块检索和格式化服务器时间之后,该date()函数通过在HTTP响应中发送结果来结束:

const formattedDate = moment().format(format);
console.log('Sending Formatted date:', formattedDate);
res.status(200).send(formattedDate);
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因此,在您的代码中,您可以在响应中发回令牌send(),例如:

// ...
// Create a Firebase custom auth token.
return admin.auth().createCustomToken(uid, additionalClaims).then((token) => {
  console.log('Created Custom token for UID "', uid, '" Token:', token);
  res.status(200).send(token);
  return token;
});
// ...
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