Hibernate继承与不同的主键

Raf*_*ima 4 java inheritance hibernate table-per-class mappedsuperclass

我正在尝试使用TABLE_PER_CLASS策略创建继承,但我想为每个表创建不同的主键是否可能?

我有一个类Register,它有数百万个实例,其中一些实例是"特殊的",并且对于它们的列和额外的列有不同的规则.

@MappedSuperclass

public abstract class Register {


    @Id
    @Column(nullable = false, unique = true, updatable = false)
    private Long userId;


    private Date checked;

    @Column(nullable = false)
    private RegisterState tipo;
}


@Entity
@AttributeOverrides({ @AttributeOverride(name = "userId", column = @Column(nullable = false, unique = false, updatable = false)) })
public class PotencialRegister extends Register implements Serializable {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Integer id;


    @Column(length = 64, nullable = false, unique = false)
    private String referer;
}
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对于基本注册我不需要一个Id属性,因为我有一个独特的列,但该列不是唯一的专业机构,所以我增加了一个额外的属性.

问题是hibernate使用父id创建了一个复合主键(生成的模式是):

create table PotencialRegister (
        id integer not null,
        userId bigint not null,
        checked datetime(6),
        tipo integer not null,
        referer varchar(64) not null,
        primary key (id, userId)
    )  

    create table Register (
        userId bigint not null,
        checked datetime(6),
        tipo integer not null,
        primary key (userId)
    )  
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列是正确的,schama是我想要的,但我想从PotencialRegister主键中删除"id"成员.

Rav*_*vik 6

您可以创建另一个没有@Id列的类,并将此类用作每种类型的Register的基类.

所以你的Register类看起来像:

@MappedSuperclass

public abstract class Register {

    @Column(nullable = false, unique = true, updatable = false)
    private Long userId;

    private Date checked;

   @Column(nullable = false)
    private RegisterState tipo;
}
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现在为您的普通注册,您可以执行以下操作:

 @Entity   
 public class NormalRegister extends Register implements Serializable{

    @Id
    public Long getUserId(){
      return super.userId;
    }

     public void setUserId(Long uId){
        super.userId=uId;
      }

   }
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接下来,将PotencialRegister类定义为:

@Entity
@AttributeOverrides({ @AttributeOverride(name = "userId", column = @Column(nullable = false, unique = false, updatable = false)) })
public class PotencialRegister extends Register implements Serializable {

    private Integer id;


    @Column(length = 64, nullable = false, unique = false)
    private String referer;

    @Id
    public Long getUserId(){
      return super.userId;
    }

     public void setUserId(Long uId){
        super.userId=uId;
      }

}
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有了这个,你没有基类中的Id,所有子类都可以定义自己的Id属性