Raf*_*ima 4 java inheritance hibernate table-per-class mappedsuperclass
我正在尝试使用TABLE_PER_CLASS策略创建继承,但我想为每个表创建不同的主键是否可能?
我有一个类Register,它有数百万个实例,其中一些实例是"特殊的",并且对于它们的列和额外的列有不同的规则.
@MappedSuperclass
public abstract class Register {
@Id
@Column(nullable = false, unique = true, updatable = false)
private Long userId;
private Date checked;
@Column(nullable = false)
private RegisterState tipo;
}
@Entity
@AttributeOverrides({ @AttributeOverride(name = "userId", column = @Column(nullable = false, unique = false, updatable = false)) })
public class PotencialRegister extends Register implements Serializable {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Integer id;
@Column(length = 64, nullable = false, unique = false)
private String referer;
}
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对于基本注册我不需要一个Id属性,因为我有一个独特的列,但该列不是唯一的专业机构,所以我增加了一个额外的属性.
问题是hibernate使用父id创建了一个复合主键(生成的模式是):
create table PotencialRegister (
id integer not null,
userId bigint not null,
checked datetime(6),
tipo integer not null,
referer varchar(64) not null,
primary key (id, userId)
)
create table Register (
userId bigint not null,
checked datetime(6),
tipo integer not null,
primary key (userId)
)
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列是正确的,schama是我想要的,但我想从PotencialRegister主键中删除"id"成员.
您可以创建另一个没有@Id列的类,并将此类用作每种类型的Register的基类.
所以你的Register类看起来像:
@MappedSuperclass
public abstract class Register {
@Column(nullable = false, unique = true, updatable = false)
private Long userId;
private Date checked;
@Column(nullable = false)
private RegisterState tipo;
}
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现在为您的普通注册,您可以执行以下操作:
@Entity
public class NormalRegister extends Register implements Serializable{
@Id
public Long getUserId(){
return super.userId;
}
public void setUserId(Long uId){
super.userId=uId;
}
}
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接下来,将PotencialRegister类定义为:
@Entity
@AttributeOverrides({ @AttributeOverride(name = "userId", column = @Column(nullable = false, unique = false, updatable = false)) })
public class PotencialRegister extends Register implements Serializable {
private Integer id;
@Column(length = 64, nullable = false, unique = false)
private String referer;
@Id
public Long getUserId(){
return super.userId;
}
public void setUserId(Long uId){
super.userId=uId;
}
}
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有了这个,你没有基类中的Id,所有子类都可以定义自己的Id属性
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