如何在Java Application中播放音频

Question

我正在制作一个java应用程序,我需要播放音频.我正在播放我的大炮射击的小声音文件(它是一个大炮射击游戏)和射弹爆炸,虽然我打算循环播放背景音乐.我找到了两种不同的方法来实现这一目标,但两种方法都无法实现我想要的效果.

第一种方法实际上是一种方法:

        public void playSoundFile(File file) {//http://java.ittoolbox.com/groups/technical-functional/java-l/sound-in-an-application-90681

        try {
//get an AudioInputStream
            AudioInputStream ais = AudioSystem.getAudioInputStream(file);
//get the AudioFormat for the AudioInputStream
            AudioFormat audioformat = ais.getFormat();
            System.out.println("Format: " + audioformat.toString());
            System.out.println("Encoding: " + audioformat.getEncoding());
            System.out.println("SampleRate:" + audioformat.getSampleRate());
            System.out.println("SampleSizeInBits: " + audioformat.getSampleSizeInBits());
            System.out.println("Channels: " + audioformat.getChannels());
            System.out.println("FrameSize: " + audioformat.getFrameSize());
            System.out.println("FrameRate: " + audioformat.getFrameRate());
            System.out.println("BigEndian: " + audioformat.isBigEndian());
//ULAW format to PCM format conversion
            if ((audioformat.getEncoding() == AudioFormat.Encoding.ULAW)
                    || (audioformat.getEncoding() == AudioFormat.Encoding.ALAW)) {
                AudioFormat newformat = new AudioFormat(AudioFormat.Encoding.PCM_SIGNED,
                        audioformat.getSampleRate(),
                        audioformat.getSampleSizeInBits() * 2,
                        audioformat.getChannels(),
                        audioformat.getFrameSize() * 2,
                        audioformat.getFrameRate(), true);
                ais = AudioSystem.getAudioInputStream(newformat, ais);
                audioformat = newformat;
            }

//checking for a supported output line
            DataLine.Info datalineinfo = new DataLine.Info(SourceDataLine.class, audioformat);
            if (!AudioSystem.isLineSupported(datalineinfo)) {
                //System.out.println("Line matching " + datalineinfo + " is not supported.");
            } else {
                //System.out.println("Line matching " + datalineinfo + " is supported.");
//opening the sound output line
                SourceDataLine sourcedataline = (SourceDataLine) AudioSystem.getLine(datalineinfo);
                sourcedataline.open(audioformat);
                sourcedataline.start();
//Copy data from the input stream to the output data line
                int framesizeinbytes = audioformat.getFrameSize();
                int bufferlengthinframes = sourcedataline.getBufferSize() / 8;
                int bufferlengthinbytes = bufferlengthinframes * framesizeinbytes;
                byte[] sounddata = new byte[bufferlengthinbytes];
                int numberofbytesread = 0;
                while ((numberofbytesread = ais.read(sounddata)) != -1) {
                    int numberofbytesremaining = numberofbytesread;
                    sourcedataline.write(sounddata, 0, numberofbytesread);
                }
            }

        } catch (Exception e) {
            e.printStackTrace();
        }
    }

这个问题是我的整个程序停止,直到声音文件完成,或至少接近完成.

第二种方法是这样的:

    File file = new File("Launch1.wav");
    AudioClip clip;
    try {
        clip = JApplet.newAudioClip(file.toURL());
        clip.play();
    } catch (Exception e) {
        e.getMessage();
    }

我在这里遇到的问题是每次声音文件提前结束或根本不播放取决于我放置代码的位置.

没有上述问题,他们是否可以播放声音？难道我做错了什么？任何帮助是极大的赞赏.

Answer 1

对于第一种方法,您必须为音频创建另一个线程.

例如这样:

new Thread(
            new Runnable() {
                public void run() {
                    try {
                        // PLAY AUDIO CODE
                    } catch (Exception e) {
                        e.printStackTrace();
                    }
                }
            }).start();

当然,你必须确保以前的声音还没有播放.