从hashmap对象中删除值的有效方法

use*_*125 1 java hashmap

我有HashMap对象包含一个x-y-z具有相应值的键test-test1-test2.

Map<String,String> map = new HashMap<String,String>(); 
map.put("x-y-z","test-test1-test2");
map.put("x1-y1-z1","test-test2-test3"); 
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现在我有一个输入字符串数组,其中包含一些键:

String[] rem={"x","x1"}
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基于这个字符串数组,我想删除HashMap值.

任何人都可以提供有效的方法来执行此操作吗?

Mar*_*dou 5

List remList = Arrays.asList(rem);
for (Iterator it = map.keySet().iterator(); it.hasNext();) {
    String key = (String) it.next();
    String[] tokens = key.split("-");
    for (int i = 0; i < tokens.length; i++) {
        String token = tokens[i];
        if (remList.contains(token)) {
            it.remove();
            break;
        }
     }
}
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以及根据您对此答案的最新评论添加功能的更新版本:

private static Map getMapWithDeletions(Map map, String[] rem) {
    Map pairs = new HashMap();
    for (int i = 0; i < rem.length; i++) {
        String keyValue = rem[i];
        String[] pair = keyValue.split("@", 2);
        if (pair.length == 2) {
            pairs.put(pair[0], pair[1]);
        }
    }
    Set remList = pairs.keySet();
    for (Iterator it = map.keySet().iterator(); it.hasNext();) {
        String key = (String) it.next();
        String[] tokens = key.split("-");
        for (int i = 0; i < tokens.length; i++) {
            String token = tokens[i];
            if (remList.contains(token)) {
                it.remove();
                pairs.remove(token);
                break;
            }
        }
    }
    map.putAll(pairs);
    return map;
}
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