如何以编程方式检查"Face Id"和"Touch Id"的支持

Question

我已经为我的应用程序安全目的集成了LocalAuthentication,它一直支持基于"Touch Id"的支持.但是现在,苹果最近还增加了"基于身份识别"的身份验证.

如何检查设备支持哪种类型的身份验证.触摸ID或面部ID？

Answer 1

我一直在努力让这个工作,并发现我需要使用LAContext的单个实例,并且需要在获取 biometryType之前调用LAContextInstance .canEvaluatePolicy(.deviceOwnerAuthenticationWithBiometrics,error:nil).这是我的最终代码,支持旧的iOS版本:

import LocalAuthentication

static func biometricType() -> BiometricType {
    let authContext = LAContext()
    if #available(iOS 11, *) {
        let _ = authContext.canEvaluatePolicy(.deviceOwnerAuthenticationWithBiometrics, error: nil)
        switch(authContext.biometryType) {
        case .none:
            return .none
        case .touchID:
            return .touch
        case .faceID:
            return .face
        }
    } else {
        return authContext.canEvaluatePolicy(.deviceOwnerAuthenticationWithBiometrics, error: nil) ? .touch : .none
    }
}

enum BiometricType {
    case none
    case touch
    case face
}

Answer 2

使用Xcode 9,查看LocalAuthentication - > LAContext - > LABiometryType.

LABiometryType是一个枚举,其值与附加图像相同

您可以在Touch ID和FaceID之间检查设备支持的身份验证类型,或者不检查.

编辑:

Apple已更新此枚举LABiometryType的值.none现在已弃用.

Answer 3

因为我是扩展的忠实粉丝。我对这个答案的措辞有些不同。本质是一样的。这是一个插件扩展。

import LocalAuthentication

extension LAContext {
    enum BiometricType: String {
        case none
        case touchID
        case faceID
    }

    var biometricType: BiometricType {
        var error: NSError?

        guard self.canEvaluatePolicy(.deviceOwnerAuthenticationWithBiometrics, error: &error) else {
            // Capture these recoverable error thru Crashlytics
            return .none
        }

        if #available(iOS 11.0, *) {
            switch self.biometryType {
            case .none:
                return .none
            case .touchID:
                return .touchID
            case .faceID:
                return .faceID
            }
        } else {
            return  self.canEvaluatePolicy(.deviceOwnerAuthenticationWithBiometrics, error: nil) ? .touchID : .none
        }
    }
}

像这样使用：

var currentType = LAContext().biometricType

Answer 4

目标C :)

/** Only interesting devices are enumerated here. To change view constraints depending
 on screen height. Or the top notch for iPhone X
 */
typedef NS_ENUM(NSUInteger, BPDeviceType) {
    BPDeviceTypeUnknown,
    BPDeviceTypeiPhone4,
    BPDeviceTypeiPhone5,
    BPDeviceTypeiPhone6,
    BPDeviceTypeiPhone6Plus,
    BPDeviceTypeiPhone7,
    BPDeviceTypeiPhone7Plus,
    BPDeviceTypeiPhoneX,
    BPDeviceTypeiPad
};

+ (BPDeviceType)getDeviceType {
    double screenHeight = [[UIScreen mainScreen] bounds].size.height;
    if(UI_USER_INTERFACE_IDIOM()==UIUserInterfaceIdiomPad)
    {
        return BPDeviceTypeiPad;

    } else if (UI_USER_INTERFACE_IDIOM()== UIUserInterfaceIdiomPhone)
    {
        if (@available(iOS 11, *)) {
            UIEdgeInsets insets = [UIApplication sharedApplication].delegate.window.safeAreaInsets;
            if (insets.top > 0) {
                return BPDeviceTypeiPhoneX;
            }
        }

        if(screenHeight == 480) {
            return BPDeviceTypeiPhone4;
        } else if (screenHeight == 568) {
            return BPDeviceTypeiPhone5;
        } else if (screenHeight == 667) {
            return BPDeviceTypeiPhone6;
        } else if (screenHeight == 736) {
            return BPDeviceTypeiPhone6Plus;
        }
    }
    return BPDeviceTypeUnknown;
}

+ (BOOL) isBiometricIDAvailable {
    if (![LAContext class]) return NO;

    LAContext *myContext = [[LAContext alloc] init];
    NSError *authError = nil;
    if (![myContext canEvaluatePolicy:LAPolicyDeviceOwnerAuthenticationWithBiometrics error:&authError]) {
        NSLog(@"%@", [authError localizedDescription]);
        return NO;
    }
    return YES;
}

+ (BOOL) isTouchIDAvailable {
    if (![LAContext class]) return NO;

    LAContext *myContext = [[LAContext alloc] init];
    NSError *authError = nil;
    if (![myContext canEvaluatePolicy:LAPolicyDeviceOwnerAuthenticationWithBiometrics error:&authError]) {
        NSLog(@"%@", [authError localizedDescription]);
        return NO;
        // if (authError.code == LAErrorTouchIDNotAvailable) {}
    }

    if (@available(iOS 11.0, *)) {
        if (myContext.biometryType == LABiometryTypeTouchID){
            return YES;
        } else {
            return NO;
        }
    } else {
        return YES;
    }
}

+ (BOOL) supportFaceID {
    return [BPDeviceInfo getDeviceType] == BPDeviceTypeiPhoneX;
}

+ (BOOL) isFaceIDAvailable {
    if (![LAContext class]) return NO;

    LAContext *myContext = [[LAContext alloc] init];
    NSError *authError = nil;
    if (![myContext canEvaluatePolicy:LAPolicyDeviceOwnerAuthenticationWithBiometrics error:&authError]) {
        NSLog(@"%@", [authError localizedDescription]);
        return NO;
    }

    if (@available(iOS 11.0, *)) {
        if (myContext.biometryType == LABiometryTypeFaceID){
            return YES;
        } else {
            return NO;
        }
    } else {
        return NO;
    }
}

Answer 5

我为本地身份验证创建了一个单例类，因为它有助于使用static整个应用程序的属性一次初始化一个实例。

import Foundation
import LocalAuthentication

public class LocalAuthManager: NSObject {

    public static let shared = LocalAuthManager()
    private let context = LAContext()
    private let reason = "Your Request Message"
    private var error: NSError?

    enum BiometricType: String {
        case none
        case touchID
        case faceID
    }

    private override init() {

    }

    // check type of local authentication device currently support
    var biometricType: BiometricType {
        guard self.context.canEvaluatePolicy(.deviceOwnerAuthenticationWithBiometrics, error: &error) else {
            return .none
        }

        if #available(iOS 11.0, *) {
            switch context.biometryType {
            case .none:
                return .none
            case .touchID:
                return .touchID
            case .faceID:
                return .faceID
            }
        } else {
            return self.context.canEvaluatePolicy(.deviceOwnerAuthentication, error: nil) ? .touchID : .none
        }
    }
}

执行：

func checkAuth() {
     let authType = LocalAuthManager.shared.biometricType
        switch authType {
        case .none:
            print("Device not registered with TouchID/FaceID")
        case .touchID:
            print("Device support TouchID")
        case .faceID:
            print("Device support FaceID")
        }
 }

Answer 6

这是通过属性的另一种方式（例如，在您的访问实例上）。

import LocalAuthentication


enum BiometricType {
    case none
    case touchID
    case faceID
}

var biometricType: BiometricType {
    get {
        let context = LAContext()
        var error: NSError?

        guard context.canEvaluatePolicy(.deviceOwnerAuthenticationWithBiometrics, error: &error) else {
            print(error?.localizedDescription ?? "")
            return .none
        }

        if #available(iOS 11.0, *) {
            switch context.biometryType {
            case .none:
                return .none
            case .typeTouchID:
                return .touchID
            case .typeFaceID:
                return .faceID
            }
        } else {
            return  .touchID
        }
    }
}

Answer 7

iOS 11上提供人脸ID，默认情况下，iPhone X随iOS 11一起提供。在LocalAuth框架中，他们添加了“ biometryType”属性，该属性使您能够检测设备上是否存在Face ID。

/// checks if face id is avaiable on device
func faceIDAvailable() -> Bool {
    if #available(iOS 11.0, *) {
        let context = LAContext()
        return (context.canEvaluatePolicy(LAPolicy.deviceOwnerAuthentication, error: nil) && context.biometryType == .faceID)
    }
    return false
}

Answer 8

这是我的“助手类”，它还包括密码

enum BiometryType: String {
    case none = "None"
    case faceID = "Face ID"
    case touchID = "Touch ID"
    case passcode = "Passcode"
}


var biometryType: BiometryType {
    let myContext = LAContext()

    let hasAuthenticationBiometrics = myContext.canEvaluatePolicy(.deviceOwnerAuthenticationWithBiometrics, error: nil)
    let hasAuthentication = myContext.canEvaluatePolicy(.deviceOwnerAuthentication, error: nil)

    if #available(iOS 11.0, *) {
        if hasAuthentication {
            if hasAuthenticationBiometrics {
                switch myContext.biometryType {
                case .none: return .none
                case .faceID: return .faceID
                case .touchID: return .touchID
                }
            } else {
                return .passcode
            }
        } else {
            return .none
        }
    } else {
        if hasAuthentication {
            if hasAuthenticationBiometrics {
                return .touchID
            } else {
                return .passcode
            }
        } else {
            return .none
        }
    }
}