在 Node.js 中从 AudioBuffer 写入一个 wav 文件

fas*_*399 4 javascript node.js audiocontext

我是 Node.js 编程新手,我正在尝试将 m4a 文件转换为 wav 文件。

我使用了 audiobuffer-to-wav 和 web-audio-api。这是我的代码:

const fs = require('fs');
const toWav = require('audiobuffer-to-wav');
const AudioContext = require('web-audio-api').AudioContext;
const audioContext = new AudioContext;

let resp = fs.readFileSync('sample.m4a');

audioContext.decodeAudioData(resp, buffer => {
  let wav = toWav(buffer);
  console.log(buffer.length);
  console.log(wav); 
});
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我想知道如何将 wav 变量保存到 Node.js 中的文件中

fas*_*399 6

const fs = require('fs');
const toWav = require('audiobuffer-to-wav');
const AudioContext = require('web-audio-api').AudioContext;
const audioContext = new AudioContext;
 let resp = fs.readFileSync('sample.m4a');

var audioStack = [];

var header = require('waveheader');

audioContext.decodeAudioData(resp, buffer => {
    let wav = toWav(buffer); 
    var chunk = new Uint8Array(wav);
    console.log(chunk); 
    fs.appendFile('bb.wav', new Buffer(chunk), function (err) {
    });

});
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这是我的回答。谢谢卡拉马里科。