通过从Scanner读取行来实例化ArrayList,在哪里声明对象?

sma*_*ish 3 java arrays arraylist java.util.scanner

我想用输入文件中的行填充数组列表,输入文件如下所示:

7f00000000000000000000000000000000000000000000000000000000000000027f00000000000000000000000000000000000000000000000000000000000000027f00000000000000000000000000000000000000000000000000000000000000020101
7f00000000000000000000000000000000000000000000000000000000000000037f00000000000000000000000000000000000000000000000000000000000000037f00000000000000000000000000000000000000000000000000000000000000030101
7f00000000000000000000000000000000000000000000000000000000000000047f00000000000000000000000000000000000000000000000000000000000000047f00000000000000000000000000000000000000000000000000000000000000040101
7f00000000000000000000000000000000000000000000000000000000000000057f00000000000000000000000000000000000000000000000000000000000000057f00000000000000000000000000000000000000000000000000000000000000050101
7f00000000000000000000000000000000000000000000000000000000000000067f00000000000000000000000000000000000000000000000000000000000000067f00000000000000000000000000000000000000000000000000000000000000060101
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我想基于此创建的Java中的数据对象将这些行中的每一行作为新字符串,并且它们将一起存在于列表中,可以这么说*.

因此,在我尝试将文件行读入此数组列表的不同组件时,我无法弄清楚我需要在主程序中声明数组列表的位置.我的计划是用一个单独的方法填充它:

import java.io.*;
import java.util.Scanner;
import java.util.List;
import java.util.Array;
import java.util.ArrayList;

class evmTest {

public static void main(String[] args) {


    Array<String> inputLinesObject = new ArrayList<String>();

    // populate from file
    inputLinesObject = readFile("/Users/s.matthew.english/codes.txt", inputLinesObject);


    System.out.println(Array.toString(inputLinesObject));

}

    private static void readFile(String fileName, Array<String> inputLines) {
        try {
            File file = new File(fileName);
            Scanner scanner = new Scanner(file);
            while (scanner.hasNextLine()) {
                // System.out.println(scanner.nextLine());
                inputLines.add(scanner.nextLine());
            }
            scanner.close();
        } catch (FileNotFoundException e) {
            e.printStackTrace();
        }
        return inputLines;
    }

}
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也许我最初可以将其实例化为null,然后将该null数组列表传递给要填充的方法?

*最后一句话中的术语并不完全准确 - 请原谅我 - 我正在重新调整Java的词汇量,但我认为它应该足够清楚我正在尝试做什么.如果没有,请告诉我,我将很乐意澄清.

Dam*_*mCx 6

对于您的测试,您只需在try上方实例化ArrayList

import java.io.File;
import java.io.FileNotFoundException;
import java.util.ArrayList;
import java.util.List;
import java.util.Scanner;

public class EvmTest {

    public static void main(final String[] args) {
        // populate from file
        final List<String> inputLinesObject = EvmTest.readFile("/Users/s.matthew.english/codes.txt");

        for (final String line : inputLinesObject) {
            System.out.println(line);
        }
    }

    private static List<String> readFile(final String fileName) {
        final List<String> inputLinesObject = new ArrayList<>();

        try {
            final File file = new File(fileName);
            final Scanner scanner = new Scanner(file);
            while (scanner.hasNextLine()) {
                // System.out.println(scanner.nextLine());
                inputLinesObject.add(scanner.nextLine());
            }
            scanner.close();
        } catch (final FileNotFoundException e) {
            e.printStackTrace();
        }
        return inputLinesObject;
    }
}
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这有两个好处: - 您不修改readFile方法的输入参数 - 您不必处理List为空或null的情况