如何将浮点数转换为时间？

Question

举个例子可以说我有float total_Time = 228.10803我想要的是转换total_Time成时间格式所以它看起来像这样00:03:48我怎么做？

我想这样写:

{

    float total_Time = 0;
    float h = 0;
    float m = 0;
    float s = 0;

    br.BaseStream.Position = i + 4;
    total_Time = br.ReadSingle(); //reads 228.10803
    total_Time = Convert.ToSingle(Math.Round(total_Time, 0));
    if (total_Time < 3600)
    {
        h = 0;
    }
    else
    {
        h = total_Time / 3600;
        h = Convert.ToSingle(Math.Round(h, 0));
        total_Time = total_Time - (h * 3600);
    }
    m = total_Time / 60;
    m = Convert.ToSingle(Math.Round(m, 0));
    total_Time = total_Time - (m * 60);
    s = total_Time;
    s = Convert.ToSingle(Math.Round(s, 0));
    SaveCS_PlayTime.Text = String.Format("Play Time: {0}:{1}:{2}", h, m, s);
}

但出于某种原因,它表明它是这样的00:4:-12.也许我犯了一个错误.真的需要一些帮助.我知道有些帖子的标题与我的标题几乎相同,但没有我想要的答案.

Answer 1

听起来你应该把它转换为a TimeSpan然后格式化:

using System;

class Test
{
    static void Main()
    {
        float totalSeconds = 228.10803f;
        TimeSpan time = TimeSpan.FromSeconds(totalSeconds);
        Console.WriteLine(time.ToString("hh':'mm':'ss")); // 00:03:48
    }
}

另一种方法是使用我的Noda Time库,在那里你构建一个Duration然后格式化它.