Ric*_*ica 6 python typing namedtuple
我期待使用有点新的typing.NamedTuple类,它允许使用通常的Python类语法创建命名元组类(包括添加文档字符串和方法,提供默认值,类型提示等等).
但是:底部的类产生以下错误消息:
AttributeError: Cannot overwrite NamedTuple attribute __new__
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从中我收集它所说的内容:压倒一切__new__仍然是禁忌.这非常令人失望.
解决这个问题的"旧方法"是从一个命名的元组类继承,但这需要我认为是一些丑陋的样板代码:
from collections import namedtuple
class FormatSpec(namedtuple('FormatSpecBase', 'fill align sign alt zero '
'width comma decimal precision type')):
__slots__ = ()
def __new__(cls, fill, align, sign, alt, zero,
width, comma, decimal, precision, type):
to_int=lambda x: int(x) if x is not None else x
zero=to_int(zero)
width=to_int(width)
precision=to_int(precision)
return super().__new__(cls, fill, align, sign, alt, zero,
width, comma, decimal, precision, type)
FormatSpec.__doc__=_FormatSpec.__doc__.replace('FormatSpecBase','FormatSpec')
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是否有一些其他的替代方法可以让我投的zero,width和precision论据下面int之前创建一个名为元组的,但仍然使用相同的类创建语法?还是我坚持使用旧的方式?
from typing import NamedTuple, Optional
class FormatSpec(NamedTuple):
"""Represents a string that conforms to the [Format Specification
Mini-Language][1] in the string module.
[1]: https://docs.python.org/3/library/string.html#formatspec
"""
fill: Optional[str]
align: Optional[str]
sign: Optional[str]
alt: Optional[str]
zero: Optional[int]
width: Optional[int]
comma: Optional[str]
decimal: Optional[str]
precision: Optional[int]
type: str
def __new__(cls, fill, align, sign, alt, zero, width, comma, decimal, precision, type):
to_int=lambda x: int(x) if x is not None else x
zero=to_int(zero)
width=to_int(width)
precision=to_int(precision)
return super().__new__(cls, fill, align, sign, alt, zero,
width, comma, decimal, precision, type)
def join(self):
return ''.join('{!s}'.format(s) for s in self if s is not None)
def __format__(self, format_spec):
try:
return format(self.join(), format_spec)
except (TypeError, ValueError):
return super().__format__(format_spec)
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一种方法是将其分为两个类,并在子类中进行参数修改:
from typing import NamedTuple, Optional
class FormatSpecBase(NamedTuple):
"""Represents a string that conforms to the [Format Specification
Mini-Language][1] in the string module.
[1]: https://docs.python.org/3/library/string.html#formatspec
"""
fill: Optional[str]
align: Optional[str]
sign: Optional[str]
alt: Optional[str]
zero: Optional[int]
width: Optional[int]
comma: Optional[str]
decimal: Optional[str]
precision: Optional[int]
type: str
def join(self):
return ''.join('{!s}'.format(s) for s in self if s is not None)
def __format__(self, format_spec):
try:
return format(self.join(), format_spec)
except (TypeError, ValueError):
return super().__format__(format_spec)
class FormatSpec(FormatSpecBase):
__slots__ = ()
def __new__(cls, fill, align, sign, alt, zero, width, comma, decimal, precision, type):
to_int=lambda x: int(x) if x is not None else x
zero=to_int(zero)
width=to_int(width)
precision=to_int(precision)
return super().__new__(cls, fill, align, sign, alt, zero,
width, comma, decimal, precision, type)
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我不太喜欢这种方法,但至少它比“旧方法”更具可读性(尽管它仍然需要那些悬而未决的__slots__废话)。
另一种方式是工厂:
def MakeFormatSpec(cls, fill, align, sign, alt, zero,
width, comma, decimal, precision, type):
to_int=lambda x: int(x) if x is not None else x
zero=to_int(zero)
width=to_int(width)
precision=to_int(precision)
return FormatSpec(fill, align, sign, alt, zero,
width, comma, decimal, precision, type)
fspec = MakeFormatSpec(*parse_format_spec(some_format_spec_string))
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...或工厂方法:
@classmethod
def make(cls, fill, align, sign, alt, zero, width, comma, decimal, precision, type):
to_int=lambda x: int(x) if x is not None else x
zero=to_int(zero)
width=to_int(width)
precision=to_int(precision)
return cls(fill, align, sign, alt, zero,
width, comma, decimal, precision, type)
fspec = FormatSpec.make(*parse_format_spec(some_format_spec_string))
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然而,与简单地能够做到的相比,这些都相当笨重:
fspec = FormatSpec(*parse_format_spec(some_format_spec_string))
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