从Python中的列表中删除单引号

Question

我有一个输入字符串:

result = '"testing","0.8841","642000.0","80.014521","-60.940653","4522126666","1500854400","","1500842014000","name","80.014521","-60.996532","sampledevice","3","name"'

data = result.split("\n")

i = 0
while i < len(data):
    i = i +1 
    dd = data[i].split(',')
    print dd
    break

并将相应的输出为:

[
  '"testing"',
  '"0.8841"',
  '"642000.0"',
  '"80.014521"',
  '"-60.940653"',
  '"4522126666"',
  '"1500854400"',
  '""',
  '"1500842014000"',
  '"name"',
  '"80.014521"',
  '"-60.996532"',
  '"sampledevice"',
  '"3"',
  '"name"'
]

如何从列表中的每个元素中删除单引号？

Answer 1

你需要申请strip删除字符串两边的引号.

dd = [x.strip('"') for x in data[i].split(',')]

那说,你的循环似乎有一个索引问题.应该重写,例如:

result = '"testing","0.8841","642000.0","80.014521","-60.940653","4522126666","1500854400"\n"1500842014000","name","80.014521","-60.996532","sampledevice","3","name"'

for line in result.splitlines():
    dd = [x.strip('"') for x in line.split(',')]
    print(dd)

在这一点上,你会变得更好

dd = ast.literal_eval(line)

还有csv一个list输入完全使用模块(不需要传递文件句柄)(不要传递string,因为它会产生一些奇怪的效果)

导入csv

import csv
for row in csv.reader(result.splitlines()):
    print(row)

所有导致:

['testing', '0.8841', '642000.0', '80.014521', '-60.940653', '4522126666', '1500854400']
['1500842014000', 'name', '80.014521', '-60.996532', 'sampledevice', '3', 'name']

Answer 2

将文本视为CSV:

import csv
import StringIO

result = '"testing","0.8841","642000.0","80.014521","-60.940653","4522126666","1500854400","","1500842014000","name","80.014521","-60.996532","sampledevice","3","name"'
print next(csv.reader(StringIO.StringIO(result)))

给你:

['testing', '0.8841', '642000.0', '80.014521', '-60.940653', '4522126666', '1500854400', '', '1500842014000', 'name', '80.014521', '-60.996532', 'sampledevice', '3', 'name']

Answer 3

拆分前替换双引号：

>>> result.replace('"', '').split(',')
['testing', '0.8841', '642000.0', '80.014521', '-60.940653', '4522126666', '1500854400', '', '1500842014000', 'name', '80.014521', '-60.996532', 'sampledevice', '3', 'name']

Answer 4

literal_eval 是解决这个问题的好方法

import ast
dd = [ast.literal_eval(i) for i in data]