Spring登录表单示例

Question

我尝试在谷歌搜索,但我找不到任何好的例子,其中用数据库检查用户名和密码以进行身份​​验证.

换句话说,如何使用Spring和Hibernate创建一个简单的登录表单,其中使用数据库检查凭据.

更新

Cam有没有想出一个简单的例子,我可以看到流程如何以及输入数据如何传递给hibernate？

Answer 1

首先,您应该定义此文件WEB-INF/spring/serurity-context.xml:

<beans:beans xmlns="http://www.springframework.org/schema/security"
             xmlns:beans="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
             xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.0.xsd
                                 http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-2.0.1.xsd">

    <http auto-config="true" />

    <beans:bean id="myUserService" class="org.my.UserService" />
    <authentication-provider user-service-ref="myUserService" />

</beans:beans>

现在你应该创建org.my.UserService类和实现接口org.springframework.security.core.userdetails.UserDetailsService.这个接口有一个方法:

UserDetails loadUserByUsername(String username) throws UsernameNotFoundException, org.springframework.dao.DataAccessException

在这种方法中,您可以使用Hibernate来按用户名加载用户.如果用户不存在 - 只需抛出UsernameNotFoundException,否则返回新的初始化UserDetails实例(在那里​​你可以提供很多东西,比如用户角色,帐号到期日等等).

现在来web.xml:

<web-app xmlns="http://java.sun.com/xml/ns/javaee"
         xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
         xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
         version="2.5">

    <display-name>My Webapp</display-name>

    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>
            /WEB-INF/spring/*-context.xml
        </param-value>
    </context-param>

    <filter>
        <filter-name>springSecurityFilterChain</filter-name>
        <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
    </filter>

    <filter-mapping>
        <filter-name>springSecurityFilterChain</filter-name>
        <url-pattern>/*</url-pattern>
    </filter-mapping>

    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>

    <servlet>
        <servlet-name>dispatcher</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>

    <servlet-mapping>
        <servlet-name>dispatcher</servlet-name>
        <url-pattern>/*</url-pattern>
    </servlet-mapping>

</web-app>

如果您有任何问题或出现问题,请随时问:)

PS:因此,使用UserDetailsS​​ervice,您无需检查用户帐户是否处于活动状态等密码.您只需提供有关用户提供的弹簧安全信息,userName并使用框架验证用户本身.例如,如果您使用MD5对密码进行编码,那么您可以password-encoder像这样使用:

<beans:bean id="myUserService" class="org.my.UserService" />
<authentication-provider user-service-ref="myUserService">
    <password-encoder hash="md5"/>
</authentication-provider>

更新

现在我们将更深入地探讨UserService- 我的(简化)现实世界的例子.

UserService 类:

import org.my_company.my_app.domain.User

public class UserService implements UserDetailsService {
    private UserDao userDao;

    public void setUserDao(UserDao userDao) {
        this.userDao = userDao;
    }

    public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException, DataAccessException {
        // load user
        User user = userDao.getUser(username);

        if (user != null) {

            // convert roles
            List<GrantedAuthority> roles = new ArrayList<GrantedAuthority>();
            for (Privilege p : user.getPrivileges()) {
                roles.add(new GrantedAuthorityImpl(p.getName()));
            }

            // initialize user
            SecurityUser securityUser = new SecurityUser(
                user.getUsername(),
                user.getLdapAuth() ? getLdapPassword(user.getUsername()) : user.getPassword(),
                user.getStatus() != User.Status.NOT_COMMITED, user.getStatus() != User.Status.BLOCKED, true, true,
                roles.toArray(new GrantedAuthority[0])
            );

            securityUser.setUser(user);

            return securityUser;
        } else {
            throw new UsernameNotFoundException("No user with username '" + username + "' found!");
        }
    }
}

现在SecurityUser:

import org.my_company.my_app.domain.User

public class SecurityUser extends org.springframework.security.core.userdetails.User {

    private User user;

    public User getUser() {
        return user;
    }

    public void setUser(User user) {
        this.user = user;
    }

    public SecurityUser(String username, String password, boolean enabled, boolean accountNonExpired, boolean credentialsNonExpired, boolean accountNonLocked, GrantedAuthority[] authorities) throws IllegalArgumentException {
        super(username, password, enabled, accountNonExpired, credentialsNonExpired, accountNonLocked, authorities);
    }
}

最后UserDao:

import org.my_company.my_app.domain.User

public class UserDao extends HibernateDaoSupport {

    public User getUser(String username) {
        List users = getHibernateTemplate().find("from User where username = ?", username);
        return users == null || users.size() <= 0 ? null : (User) users.get(0);
    }
}

正如你所看到的,我HibernateTemplate在这里使用过.

Answer 2

您可以在"Easy Angle"的帖子中看到基本的xml配置.他提到的"myUserService"部分是一个实现"UserDetailService"的bean,那个基本上只有一个方法可以实现,以下是

public UserDetails loadUserByUsername(String name) throws UsernameNotFoundException, DataAccessException

如果你使用Spring,那么你可能会有一个Bean来处理对用户表的访问.您可以注入该类以检索用户详细信息,例如:

    @Override
    public UserDetails loadUserByUsername(String name) throws UsernameNotFoundException, DataAccessException {

        UserTable user = userbean.getUserbyName(name);
        if (user == null) {
            throw new UsernameNotFoundException("User " + name + " not found!");
        }
        Collection<GrantedAuthority> auth = getAuthorities(user.getAuthorities());
        return new User(user.getName(), user.getPassword(), true, true, true, true, auth);
    }

现在在身份验证bean中,您只需要注入此bean并向其询问UserDetails.在那里,您可以使用它来检查凭据是否正确,如果是这样,请使用所需信息填充SecurityContext以便登录.

    @Override
    public Boolean authenticate(String username, String password) {
        UserDetails userdetail = null;
        try {
            userdetail = myUserService.loadUserByUsername(username);
        } catch (UsernameNotFoundException e) {
            return false;
        } catch (DataAccessException e) {
            return false;
        }
        if (!myUserService.encodePassword(password).equals(userdetail.getPassword())) {
            return false;
        }

        Authentication auth = new UsernamePasswordAuthenticationToken(userdetail.getUsername(), userdetail.getPassword(),
                userdetail.getAuthorities());
        SecurityContext sc = new SecurityContextImpl();

        ServletRequestAttributes attr = (ServletRequestAttributes)RequestContextHolder.currentRequestAttributes();
        attr.getRequest().getSession().setAttribute(UsernamePasswordAuthenticationFilter.SPRING_SECURITY_LAST_USERNAME_KEY, userdetail.getUsername());

        sc.setAuthentication(auth);
        SecurityContextHolder.setContext(sc);

        return true;
    }

当然那是真实版本的简化版本.在说用户经过身份验证之前,您必须执行更多检查(例如,SQLInjection)