She*_*noy 5 java android calllog
我试图在我的应用程序中显示通话记录详细信息,但 CallLog.Calls.CACHED_NAME 对于某些联系人始终返回 null,即使它是已保存的带有姓名的联系人。内置通话记录正确显示这些联系人的姓名。
这是我的代码:
protected customAdapRecent doInBackground(Void... params) {
ContentResolver resolver = context.getContentResolver();
final String[] PROJECTION = new String[] {
// CallLog.Calls.CACHED_LOOKUP_URI,
CallLog.Calls.NUMBER,
CallLog.Calls.CACHED_NAME,
CallLog.Calls.TYPE,
CallLog.Calls.DATE,
CallLog.Calls.DURATION
};
Cursor cursor = resolver.query(CallLog.Calls.CONTENT_URI, PROJECTION, null, null, CallLog.Calls.DATE + " DESC");
if(cursor.getCount() > 0)
{
int iNumber = cursor.getColumnIndex(CallLog.Calls.NUMBER);
int iName = cursor.getColumnIndex(CallLog.Calls.CACHED_NAME);
int iType = cursor.getColumnIndex(CallLog.Calls.TYPE);
int iDate = cursor.getColumnIndex(CallLog.Calls.DATE);
int iDuration = cursor.getColumnIndex(CallLog.Calls.DURATION);
DateFormat datePattern = DateFormat.getDateInstance(DateFormat.FULL);
String number;
String name;
String type;
String date;
String duration;
String contactId;
String callIs = "None";
String prevDate = "";
int callType;
while (cursor.moveToNext())
{
if(cursor.getString(iName) == null)
Log.e("DEBUG: ", "Position: " + cursor.getPosition());
number = cursor.getString(iNumber);
name = cursor.getString(iName);
type = cursor.getString(iType);
String tempdate = cursor.getString(iDate);
Long tempDate = Long.parseLong(tempdate);
date = datePattern.format(tempDate);
if(prevDate.equalsIgnoreCase(date))
{
prevDate = date;
date = "";
}
else
prevDate = date;
//date = new Date(Long.valueOf(strdate));
duration = cursor.getString(iDuration);
callType = Integer.parseInt(type);
switch (callType)
{
case CallLog.Calls.OUTGOING_TYPE:
callIs = "OUT";
recentRow newRowO = new recentRow(number, name, date, duration, callIs);
listItem_recentOut.add(newRowO);
break;
case CallLog.Calls.INCOMING_TYPE:
callIs = "IN";
recentRow newRowI = new recentRow(number, name, date, duration, callIs);
listItem_recentIn.add(newRowI);
break;
case CallLog.Calls.MISSED_TYPE:
callIs = "MISS";
recentRow newRowM = new recentRow(number, name, date, duration, callIs);
listItem_recentMiss.add(newRowM);
break;
}
recentRow newRow = new recentRow(number, name, date, duration, callIs);
//recentRow newRow = new recentRow(number, name, callIs);
listItem_recentAll.add(newRow);
}
cursor.close();
cAdapRecent = new customAdapRecent(context, listItem_recentAll);
}
return cAdapRecent;
}
Run Code Online (Sandbox Code Playgroud)
Log.e() 中给出的 Debug 语句也会打印。
我在查找过程中做错了什么吗?请。建议一种方法,因为我真的因此被阻止了!
提前致谢...
我还遇到了这种奇怪的行为,并发现有时您无法立即获得联系人的姓名,即使您可以从CallLog.Calls. 我注意到,自该调用后大约一小时左右,您可以获取名称以及所有其他CallLog.Calls数据。很奇怪。ContactsContract如果您需要在通话后立即刷新,您可以通过以下方式获取号码的名称:
fun getNameForNumber(context: Context, number: String): String? {
var res: String? = null
try {
val resolver = context.contentResolver
val uri = Uri.withAppendedPath(ContactsContract.PhoneLookup.CONTENT_FILTER_URI, Uri.encode(number))
val c = resolver.query(uri, arrayOf(ContactsContract.PhoneLookup.DISPLAY_NAME), null, null, null)
if (c != null) {
if (c.moveToFirst()) {
res = c.getString(c.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME))
}
c.close()
}
} catch (e: Exception) {
e.printStackTrace()
}
return res
}
Run Code Online (Sandbox Code Playgroud)
奇怪的是,当您ContactsContract按照您的方式从获取名称中获取一个名称后,通过 CallLog.Calls.CACHED_NAME ,会神秘地起作用。
这也是@PeterB 和@shyam002 的答案
| 归档时间: |
|
| 查看次数: |
1113 次 |
| 最近记录: |