路线应该声明一个屏幕.[反应原生导航错误]

Question

嗨,我是新来的反应原生,我面临奇怪的路由问题.我做错了但需要有人来指导我.

index.android.js

import { LandingScreen } from './src/components/landing_screen.js'
import HomeScreen from './src/app_component.js'
import { StackNavigator } from 'react-navigation';

const SimpleApp = StackNavigator({
  Home: { screen: HomeScreen },
  Landing: { screen: LandingScreen},
});

AppRegistry.registerComponent('HomeScreen', () => SimpleApp);

app_component.js

// Other imports ...
export default class HomeScreen extends Component {
  static navigationOptions = {
    title: 'Home Screen',
  };
  render() {
    const { navigate } = this.props.navigation;
    return (
      <View style={styles.container}>
        <Text style={styles.welcome}>
          Welcome to React Native!
        </Text>
        <Text  style={styles.instructions}> Hello CHannoo!!!</Text>
        <Text style={styles.instructions}>
          To get started, edit index.android.js
        </Text>
        <Text style={styles.instructions}>
          Double tap R on your keyboard to reload,{'\n'}
          Shake or press menu button for dev menu
        </Text>
        <Button
          title="Go to 2nd Page"
          onPress={() =>
            // alert('hello');
            navigate('LandingScreen')
            // navigate('Home', { name: 'Jane' })
          }
        />
      </View>
    );
  }

  componentDidMount () {
     SplashScreen.close({
        animationType: SplashScreen.animationType.scale,
        duration: 850,
        delay: 500,
     })
  }
}

landing_screen.js

export default class LandingScreen extends Component {
static navigationOptions = {
  title: 'Landing Screen Title',
};
render() {
  return (........)
}

如果我们删除路线着陆,它工作正常.但是当我们添加这条路线时,我们会收到错误

Route'Landing'应该声明一个屏幕.例如 ......

Answer 1

您的LandingScreen已导出为,default但您按名称导入它.

你的import语句是这样的:

import { LandingScreen } from './src/components/landing_screen.js'

用下面的行替换它(没有花括号):

import LandingScreen from './src/components/landing_screen.js'

它应该解决问题.

但是你可能会得到一个新错误,因为@Medet指出,因为你必须改变这一行:

navigate('LandingScreen')

至:

navigate('Landing')

因为您的屏幕名称是登陆.