在Perl中测试SUPER ::方法的分支分配

mab*_*e02 4 testing perl unit-testing mocking test-coverage

我即将完成研究中级Perl书籍.

在第18章中,Object Destruction引入了以下DESTROY方法定义:

# lib/Animal.pm
package Animal {
  # ...
  sub DESTROY {
    my $self = shift;
    if ($self->{temp_filename}){
      my $fh = $self->{temp_fh};
      close $fh;
      unlink $self->{temp_filename};
    }
    print '[', $self->name, " has died.]\n";
  }
# ...
}

# lib/Horse.pm
package Horse {
  use parent qw(Animal)
  # ...
  sub DESTROY {
    my $self = shift;
    $self->SUPER::DESTROY if $self->can( 'SUPER::DESTROY' );
    print "[", $self->name, " has gone off to the glue factory.]\n";
  }
# ...
}
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在几次尝试失败之后,我根据这个答案编写了这个测试:

# t/Horse.t
#!perl -T

use strict;
use warnings;
use Test::More tests => 6;
use Test::Output;
# some other tests

# test DESTROY() when SUPER::DESTROY is not defined;
{
  my $tv_horse = Horse->named('Mr. Ed');
  stdout_is( sub { $tv_horse->DESTROY }, "[Mr. Ed has died.]\n[Mr. Ed has gone off to the glue factory.]\n",
      'Horse DESTROY() when SUPER::DESTROY is defined');
}

{
  my $tv_horse = Horse->named('Mr. Ed');
  sub Animal::DESTROY { undef }
  stdout_is( sub { $tv_horse->DESTROY }, "[Mr. Ed has gone off to the glue factory.]\n",
      'Horse DESTROY() when SUPER::DESTROY is not defined');
}
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我无法在两种情况下正确测试输出,因为方法重新定义sub Animal::DESTROY { undef }也会影响前一个块中的测试.

您知道如何确保方法重新定义按预期工作吗?

谢谢

Сух*_*й27 7

这应该只设置删除/重新定义的子程序,直到封闭块结束,

{
  # not needed when removing method
  # no warnings 'redefine';

  my $tv_horse = Horse->named('Mr. Ed');
  # returns undef
  # local *Animal::DESTROY = sub { undef };

  # remove the mothod until end of the enclosing block
  local *Animal::DESTROY;

  # ..
}
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  • @ mabe02要完全删除该方法,只需本地化glob而不分配新的子:`local*Animal :: DESTROY;`就足够了. (2认同)