Typescript 继承类作为函数参数

Question

我在这里有一个打字稿问题。

I have many model classes, that are all inherited from BaseModel

class BaseModel {
    public isChecked: boolean;
}

class Animal extends BaseModel {
    public id: number;
}

class Car extends BaseModel {
    public hasHotWheels: boolean;
}

Now I need to write a function that accepts arguments that are classes that inherit from the BaseModel. I can explicitly list all the classes, but I have more than 50 models that inherit from the BaseModel class, so my question is, can I somehow state that I expect the function parameter to inherit from a said class like so

function foo( _input: inherits from BaseModel ) {} 

Answer 1

泛型可以帮助：

function foo<TModel extends BaseModel>( _input: TModel ) {}

描述泛型时可以使用许多类关键字，在 TS 路线图上有更多选项。类型推断可以轻松处理此类事情，并且当它失败时，您可以foo<FooModel>显式调用它，它仍然是类型安全的。